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2 years ago

7

What are the points that are solutions to the linear function graphed here.

1 answer:

aivan3 [116]2 years ago

4 0

-1,-2 and 1,4 are solutions

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-6c< -12<br> what will the answear be

murzikaleks [220]

Answer:c>2

Step-by-step explanation:

-6c (divide) (-6) > -12 (divide) (-6)

c>-12 (divide) (-6)

c>12 (divide) 6

c> 2

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At what points on the graph of f(x)=2x^3-6x^2-27x is the slope of the tangent line -9?

Dmitriy789 [7]

Answer:

(-1, 19) and (3, -81)

Step-by-step explanation:

f(x) = 2x³ − 6x² − 27x

f'(x) = 6x² − 12x − 27

-9 = 6x² − 12x − 27

0 = 6x² − 12x − 18

0 = x² − 2x − 3

0 = (x + 1) (x − 3)

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The points are (-1, 19) and (3, -81).

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Is 2 And 22 linear or nonlinear?

grigory [225]

Linear would be the answer

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