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3 years ago

Does anybody know the answer to this question Im having lots of problems

Mathematics

2 answers:

Dvinal [7]3 years ago

7 0

<h3>Answer: 3^9</h3>

This is the same as writing $3^9$

====================================================

How to get that answer:

The lowest height is 3^8, and the highest point is 3 times that value.

We can think of that second "3" as really 3^1. This is because x^1 = x for any real number.

Multiply 3^8 and 3^1 using the rule that a^b*a^c = a^(b+c). We add the exponents together.

Therefore, 3^8*3^1 = 3^(8+1) = 3^9

Side notes:

3^8 = 6,561
3^9 = 19,683

Lunna [17]3 years ago

3 0

Answer:

3^9

Step-by-step explanation:

3 * 3^8

3^1 * 3^8

3^1+8

= 3^9

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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.

frutty [35]

<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

$2^n\leq 2^{n+1}-2^{n-1}-1$

where n is a positive integer.

Let us take n=1

then we have:

$2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2$

Hence, the result is true for n=1.

Let us assume that the result is true for n=k

i.e.

$2^k\leq 2^{k+1}-2^{k-1}-1$

Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u> $2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Let us take n=k+1

Hence, we have:

$2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)$

( Since, the result was true for n=k )

Hence, we have:

$2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2$

Also, we know that:

$-2$

(

Since, for n=k+1 being a positive integer we have:

$2^{(k+1)+1}-2^{(k+1)-1}>0$ )

Hence, we have finally,

$2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

$2^n\leq 2^{n+1}-2^{n-1}-1$ where n is a positive integer.

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faust18 [17]

Answer:

answer to the equation is

$y = 2x + 11$

Step-by-step explanation:

$y = mx + b$

first find the slope of the line using the two points

$slope \: m = \frac{y2 - y1}{x2 - x1} = \frac{23 - 5}{6 - ( - 3)} \\ = \frac{18}{9} \\ slope \: m = 2$

substitute 2 for m and use one of the points for x and y and solve for b

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$y = 2x + 11$

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Which linear function represents the line given by the point-slope equation y – 8 = y minus 8 equals startfraction one-half endf

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The linear function which represents the line given by the point-slope equation is (B) $f(x)=\frac{1}{2} x+6$ .

<h3>What is a linear function?</h3>

The word linear function in mathematics refers to two distinct but related concepts.
A linear function in calculus and related fields is a function whose graph is a straight line, that is, a polynomial function of degree zero or one.

To find the linear function which represents the line given by the point-slope equation:

Given: $y-8=\frac{1}{2} (x-4)$

Distribute the right side:

$y-8=\frac{1}{2} (x)-\frac{1}{2} 4\\y-8=\frac{1}{2} x-2$

Adds 8 on both sides:

$y=\frac{1}{2}x-2+8\\y=\frac{1}{2}x+6$

Convert to function notation:

$f(x)=y\\f(x)=\frac{1}{2} x+6$

Therefore, the linear function which represents the line given by the point-slope equation is (B) $f(x)=\frac{1}{2} x+6$ .

Know more about linear functions here:

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The complete question is given below:

Which linear function represents the line given by the point-slope equation y – 8 = y minus 8 equals start fraction one-half end fraction left-parenthesis x minus 4 right-parenthesis. (x – 4)?

A) F(x) = f(x) equals StartFraction one-half EndFraction x plus 4.X + 4

B) f(x) = f(x) equals StartFraction one-half EndFraction x plus 6.

C) X + 6 f(x) = f(x) equals StartFraction one-half EndFraction x minus 10.X –10

D) f(x) = f(x) equals StartFraction one-half EndFraction x minus 12.X – 12

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