Ten and forty-one thousandths in expanded form and in standard
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ANSWER
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EXPLANATION
The given equations are:
y = −2x + 13
y = 2x − 3
We equate the two equations to get
−2x + 13=2x − 3
Group similar terms:
-2x-2x=-3-13
-4x=-16
Divide both sides by -4,
x=4
Put x=4 into equation (2)
y=2(4)-3
y=5
The two graphs should intersect at:
(4,5)
Answer: The probability of picking 7 and then picking a number greater than 7 is or 0.3
Step-by-step explanation: Probability
Probability shows us the chances of an event occurring.
Now, given that we have already picked three cards. therefore, 7, 8, and 9.
The number of possible outcomes is 3.
the probability of card 7,
Now, as card seven is already picked up cards 8 and 9 are the only card left.
therefore, the sample size(possible outcomes) was reduced to 2 only.
Also, cards 8 and 9 both are greater than 7, thus the desired outcome is also 2.
Further the probability of the number greater than 7 occurring,
Probability picking a number greater than 7
The probability of picking a 7 and then picking a number greater than 7
= Probability of card 7 occurring x probability of card 8 and 9 occurring.
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The length of the shorter leg is 14 inches.
We will set up two equations for this; first, for the perimeter. We will call the legs a and b:
a + b + 50 = 112
Subtract 50 from both sides:
a + b + 50 - 50 = 112 - 50
a + b = 62
We will isolate a, so we can use substitution. Subtract b from both sides:
a + b - b = 62 - b
a = 62 - b
Now we will set up our Pythagorean theorem equation:
a² + b² = 50²
a² + b² = 2500
We will substitute our value for a from the first equation into this one:
(62-b)² + b² = 2500
(62 - b)(62 - b) + b² = 2500
Multiplying the binomials, we have:
62*62 - b*62 - b*62 -b(-b) + b² = 2500
3844 - 62b - 62b + b² + b² = 2500
Combining like terms:
3844 - 124b + 2b² = 2500
To set it equal to 0 and solve, we subtract 2500 from both sides:
3844 - 124b + 2b² - 2500 = 2500 - 2500
1344 - 124b + 2b² = 0
In standard form, we have
2b² - 124b + 1344 = 0
Using the quadratic formula,
The shorter leg is 14 and the longer one is 48.
We will set up two equations for this; first, for the perimeter. We will call the legs a and b:
a + b + 50 = 112
Subtract 50 from both sides:
a + b + 50 - 50 = 112 - 50
a + b = 62
We will isolate a, so we can use substitution. Subtract b from both sides:
a + b - b = 62 - b
a = 62 - b
Now we will set up our Pythagorean theorem equation:
a² + b² = 50²
a² + b² = 2500
We will substitute our value for a from the first equation into this one:
(62-b)² + b² = 2500
(62 - b)(62 - b) + b² = 2500
Multiplying the binomials, we have:
62*62 - b*62 - b*62 -b(-b) + b² = 2500
3844 - 62b - 62b + b² + b² = 2500
Combining like terms:
3844 - 124b + 2b² = 2500
To set it equal to 0 and solve, we subtract 2500 from both sides:
3844 - 124b + 2b² - 2500 = 2500 - 2500
1344 - 124b + 2b² = 0
In standard form, we have
2b² - 124b + 1344 = 0
Using the quadratic formula,
The shorter leg is 14 and the longer one is 48.