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3 years ago

Ten and forty-one thousandths in expanded form and in standard

Mathematics

1 answer:

lyudmila [28]3 years ago

3 0

10.041 is standard form and I don't know the expanded form

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SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR

kaheart [24]

Answer:

x = 5

Step-by-step explanation:

4x + 2y + z = 24

2x - 3y - z = 2

5x + y + 2z = 21

-----------------

Eliminate z

Add the 1st and 2nd eqn

4x + 2y + z = 24

2x - 3y - z = 2

----------------

6x - 1y = 26 eqn A

Multiply the 2nd eqn by 2, then add the 3rd.

4x - 6y -2z = 4

5x + y + 2z = 21

----------------

9x - 5y = 25 eqn B

---------------

Now you have 2 eqns in 2 unknowns, not 3.

Multiply eqn A by 5 and subtract eqn B.

30x - 5y = 130 eqn A times 5

9x - 5y = 25 eqn B

-------------

21x = 105

x = 5

4 0

3 years ago

Read 2 more answers

What is the difference between -3 and -12?

rusak2 [61]

Answer:

-9

Step-by-step explanation:

all you do is 12-3 and its 9 but make sure to add the negative. Have a good day!

5 0

2 years ago

Read 2 more answers

4.7.PS-10

denis-greek [22]

Answer:

3x times 24 widgets

Step-by-step explanation:

3 0

2 years ago

PLEASE ANSWER ASAP!

Blizzard [7]

Step-by-step explanation:

Let the length of the bridge be x

Since, triangles ADF and BCF are similar, ratio of their corresponding sides are equal.

Therefore,

60 / 144 = 40 / x

X (length of the bridge) = <u>96 m</u>

4 0

3 years ago

Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc

Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

$\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m$

To find:

$\textrm{final velocity} = v = ?$

Solution:

As we know the third equation of motion is represented as

$v^{2} = u^{2} + 2\times a\times s\\$

Substituting the values u, a and s in the above equation we get

$v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\$

$v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s$

7 0

3 years ago