Answer: (f·g)(x) = -5x³ - 31x² + 62x + 18
(f·g)(-1) = -70
(fog)(x) = 25x² - 130x + 155
(fog)(-1) = 310
<u>Step-by-step explanation:</u>
f(x) = x² + 8x + 2 g(x) = -5x + 9
(f·g)(x) = (x² + 8x + 2)(-5x + 9)
= -5x³ + 9x²
- 40x² + 72x
<u> - 10x + 18</u>
= -5x³ - 31x² + 62x + 18
(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18
= -5(-1) - 31(1) - 62 + 18
= 5 - 31 - 62 + 18
= -70
****************************************************************************************
(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2
= 25x² - 90x + 81
- 40x + 72
<u> + 2</u>
= 25x² - 130x + 155
(fog)(-1) = 25(-1)² - 130(-1) + 155
= 25 + 130 + 155
= 310
<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>
Ertex angle:: x degrees
<span>base angle: x+15
</span>
The answer is shown above
Answer:
2x + 3y = 12
Step-by-step explanation:
Standard form is Ax + By = C, A, B and C must be intergers, cannot be fractions or decimals
y = -2/3x + 4 First we want to get rid of the fractions. There is only one, so if we multiply both sides by 3 that should do it.
3y = -2x + 12 Now make the constant be on one side by itself
2x + 3y = 12
Answer:
Step-by-step explanation:
Let a be the length of the altitude, then from the given triangles, applying the basic proportionality theorem, we get
![\frac{BD}{AD}=\frac{DC}{BD}](https://tex.z-dn.net/?f=%5Cfrac%7BBD%7D%7BAD%7D%3D%5Cfrac%7BDC%7D%7BBD%7D)
⇒![(BD)^{2}=DC{\times}AD](https://tex.z-dn.net/?f=%28BD%29%5E%7B2%7D%3DDC%7B%5Ctimes%7DAD)
⇒![(BD)^2=9{\times}16](https://tex.z-dn.net/?f=%28BD%29%5E2%3D9%7B%5Ctimes%7D16)
⇒![BD=\sqrt{144}](https://tex.z-dn.net/?f=BD%3D%5Csqrt%7B144%7D)
⇒![BD=12 cm](https://tex.z-dn.net/?f=BD%3D12%20cm)
Thus, the length of altitude is: 12 cm.
Now, ![\frac{AB}{AD}=\frac{AC}{AB}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BAD%7D%3D%5Cfrac%7BAC%7D%7BAB%7D)
⇒![(AB)^{2}=220](https://tex.z-dn.net/?f=%28AB%29%5E%7B2%7D%3D220)
⇒![AB= 14.83 cm](https://tex.z-dn.net/?f=AB%3D%2014.83%20cm)
Also, ![\frac{BC}{DC}\frac{AC}{BC}](https://tex.z-dn.net/?f=%5Cfrac%7BBC%7D%7BDC%7D%5Cfrac%7BAC%7D%7BBC%7D)
⇒![(BC)^{2}=400](https://tex.z-dn.net/?f=%28BC%29%5E%7B2%7D%3D400)
⇒![BC=20 cm](https://tex.z-dn.net/?f=BC%3D20%20cm)
Thus, the lengths of the legs of this triangle are 14.83 and 20 cm.