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Katen [24]
3 years ago
9

D%20%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="( \frac{10 \sqrt{3} }{ \sqrt{5} } - \sqrt{15} ) {}^{2} " alt="( \frac{10 \sqrt{3} }{ \sqrt{5} } - \sqrt{15} ) {}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Shane has 1/2 pound of cheese to make 4 sandwiches. He wants to use the same amount of cheese in each sandwich. What fraction of
anastassius [24]

Answer:

The fraction of one pound of cheese to be used in each sandwich is 1/8

Step-by-step explanation:

Here, we have a question that requires the method of dealing with the division of fractions.

To divide a fraction by a whole number, we multiply the denominator of the fraction by the whole number as follows;

\frac{x}{y} \div z =\frac{x}{y\times z}

Quantity of cheese Shane has = 1/2 pound

Number of sandwiches to be made = 4

Amount of cheese per sandwich = 1/2÷4 = 1/8.

6 0
3 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.43. The mass of the object i
brilliants [131]

Answer:

14 x 0.27 = 3.78 is your answer

Explanation:

the question is asking for the weight of the object so you multiply and get 3.79

7 0
3 years ago
A bakery used 25% more butter this month than last month. If the bakery used 240 kilograms of butter last month, how much did it
yawa3891 [41]

Answer:

300kg

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
75 000 in standard form
tatiyna

Answer:

7.5×10^4

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Hope this helps <3

7 0
3 years ago
Read 2 more answers
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
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