The answer is C <<<=====
It can't be anything else. It is not a right angle. A>90
It can't be acute because one angle is greater than 90.
It can't scalene because at least 2 of the angles (and 2 sides) are equal.

8 0

3 years ago

match each pair of points with the approximate distance between them. Round your answers to the nearest tenth.

NARA [144]

I hope it helps you.

6 0

3 years ago

Read 2 more answers

If P(x) = P<img src="https://tex.z-dn.net/?f=_%7Bn%7D" id="TexFormula1" title="_{n}" alt="_{n}" align="absmiddle" class="latex-f

seropon [69]

If $P(x) = p_nx^n + p_{n-1}x^{n-1}+\ldots+p_0$ is divided by $(x-a)$ , then $P(x) = (x-a) \cdot Q(x) + R(x)$ for some polynomials $Q,R$ . Moreover, $\deg R < 1$ (because $\deg (x-a) = 1$ ), so there exists $\alpha \in \mathbb{R}$ such that $R(x) = \alpha$ for all $x \in \mathbb{R}$ . But if we calculate $P(a)$ , it turns out that $P(a) = (a-a)\cdot Q(a) + \alpha$ , so $R(x) = \alpha = P(a)$ . $\blacksquare$

3 0

3 years ago