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Alekssandra [29.7K]
3 years ago
12

Can you get the answer and explain how you did it, i am really struggling right now

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

9514 1404 393

Answer:

 453.32

Step-by-step explanation:

The argument of the summation symbol is recognizable as the general term of a geometric series with first term a1=4 and common ratio r=1.5. The indices on the summation symbol tell you that you want the sum of the first 10 terms of the series.

The general form of the sum of the first n terms of a geometric series is ...

  Sn = a1(r^n -1)/(r -1)

For the given values of a1 and r, this sum is ...

  S_{10}=4\cdot\dfrac{1.5^{10}-1}{1.5-1}=4\cdot\dfrac{57.6650390625-1}{0.5}\\\\\boxed{S_{10}\approx453.32}

____

Your graphing calculator may be able to evaluate this for you directly.

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Answer:quasi experiment

Step-by-step explanation:

Because it is basically for comparison usually by measuring outcomes if a program by participants and non participants

8 0
3 years ago
Find the greatest common factor of 27<br> and 45<br> .
Bad White [126]

Answer:

\large\boxed{GCF(27,\ 36)=9}

Step-by-step explanation:

\begin{array}{c|c}27&3\\9&3\\3&3\\1\end{array}\\\\27=\boxed3\cdot\boxed3\cdot3\\\\\begin{array}{c|c}45&3\\15&3\\5&5\\1\end{array}\\\\45=\boxed3\cdot\boxed3\cdot5\\\\GCF(27,\ 45)=\boxed3\cdot\boxed3=9

4 0
4 years ago
Sin ^6x-cos^6÷1-sin^2x*cos^2x=1-2cos^2x<br><br>​
lilavasa [31]

Answer:

\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x  } =1-2\cos^{2} x proved.

Step-by-step explanation:

We have to prove that \frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x  } =1-2\cos^{2} x

So, the left hand side = \frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x  }

= \frac{(\sin^{2}x-\cos^{2} x )(\sin^{4} x+\cos^{4}x+\sin^{2}x \cos^{2}x)   }{{1-\sin^{2}x \cos^{2}x  }} {Since we have the formula a^{3} -b^{3}= (a-b) (a^{2}  +ab+b^{2} )}

= \frac{(\sin^{2}x-\cos^{2} x )[(\sin^{2}x+\cos^{2}x  )^{2}-2\sin^{2}x\cos^{2} x+ \sin^{2}x\cos^{2} x ]}{{1-\sin^{2}x \cos^{2}x  }} {Since we have the formula a^{2}+b^{2} = (a+b)^{2} -2ab}

= \frac{(\sin^{2}x-\cos^{2} x )(1-\sin^{2}x \cos^{2}x)}{(1-\sin^{2}x \cos^{2}x)}

= (\sin^{2}x-\cos^{2} x )

= 1-2\cos^{2} x {Since \sin^{2}x =1-\cos^{2} x}

= Right hand side

Hence, proved.

6 0
3 years ago
Factor the polynomial by its greatest common monomial factor 20y^6-15y^4+40y^2
stepladder [879]

Answer:

5y^2(4y^4 - 3y^2 +8)

Step-by-step explanation:

20y^6 - 15y^4 + 40y^2

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7 0
4 years ago
What is the solution to the square root of 3x-6 equals 3
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Answer:

x=12

Step-by-step explanation:

8 0
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