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ale4655 [162]
3 years ago
8

Find the missing factor BBB that makes the equality true. -35x^6=(-5x^2)(B)−35x 6 =(−5x 2 )(B)minus, 35, x, start superscript, 6

, end superscript, equals, left parenthesis, minus, 5, x, squared, right parenthesis, left parenthesis, B, right parenthesis B =B=B, equals
Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

B=7x^4

Step-by-step explanation:

The given equality is

-35x^6=(-5x^2)B

Take the term (-5x^2) to the left hand side. This means the term -35x^6 will be divided by (-5x^2)

\dfrac{-35x^6}{(-5x^2)}=B

Now since both the numerator and denominator have negative sign the value of fraction will be positive.

\dfrac{35x^6}{(5x^2)}=B

Now 5\times 7=35 and x^{6-2}=x^4

7x^4=B

So, the missing factor B=7x^4

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our first plot is going to be at (1,1) or 1 over and 1 up. remember points are in the form of (x,y). then (2,2)

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3 years ago
Solve the equation by completing the square.
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The sum of two numbers is 30 the difference of the two numbers is four what is the lesser number
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Find the radius of convergence, R, of the series. ∞ (−1)n (x − 6)n 4n + 1 n = 0 R =
Rina8888 [55]

I'm guessing the series is

\displaystyle\sum_{n=0}^\infty\frac{(-1)^n(x-6)^n}{4n+1}

Use the ratio test: we have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}(x-6)^{n+1}}{4n+5}}{\frac{(-1)^n(x-6)^n}{4n+1}}\right|=|x-6|\lim_{n\to\infty}\left|\frac{4n+1}{4n+5}\right|=|x-6|

The series converges for

|x-6|

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3 0
3 years ago
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