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3 years ago

What’s the answer to this

Mathematics

2 answers:

liraira [26]3 years ago

4 0

Answer:

idk what's the answer to this... so what's the question?

LuckyWell [14K]3 years ago

3 0

Am not able to see the question

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Find sin20 if sin 0 = 3; 90° < 0 < 180°

Alex777 [14]

Answer:

$\sin 2 \theta = -\dfrac{4\sqrt 5}{9}$

Step-by-step explanation:

$\text{Given that,}\\\\~~~~~~\sin \theta = \dfrac 23\\\\\implies \sin^2 \theta = \left( \dfrac 23 \right)^2\\\\\implies 1- \cos^2 \theta = \dfrac 49 \\\\\implies \cos^2 \theta = 1 - \dfrac 49 \\\\\implies \cos^2 \theta = \dfrac 59\\\\\implies \cos \theta = \pm\sqrt{\dfrac 59} \\\\\implies \cos \theta = \pm \dfrac{\sqrt 5 }3\\\\\text{Since}~ 90^\circ < \theta < 180^{\circ},~\text{the angle lies in 2nd quadrant}\left(\cos \theta ~\text{is negative}\right).\\\\$

$\text{So,}~ \cos \theta = - \dfrac{\sqrt 5 }{3}\\\\\text{Now,}\\\\\sin 2\theta = 2\sin \theta \cos \theta \\\\\\~~~~~~~~=2 \cdot \dfrac 23 \cdot \left( -\dfrac{\sqrt 5}{3} \right)\\\\\\~~~~~~~~=-\dfrac{4\sqrt 5}{9}$

$\textbf{Quadrant rule:}\\\\$

6 0

2 years ago

Find the interval on the real number line for which the radicand is nonnegative

dsp73

The answer
the complement of the question is

Find the interval on the real number line for which the radicand is nonnegative (greater than or equal to zero) so that the radical sqrt(8 x - 8) defines a real number. Leave answer in interval notation.


sqrt(8 x - 8) is definite function if 8 x - 8 ≥0, 
8 x ≥ 8 and x ≥ 8/ 8 = 1, x ≥ 1, so the interval solution is [1, infinity[

6 0

3 years ago

I need help wit this

Lina20 [59]

Answer:

1. $2

2. $4

3. 2x

Step-by-step explanation:

7 0

4 years ago

The difference of two numbers is 3. Their sum is 13. Find the numbers

tekilochka [14]

Subtract 3 from 13 you get 10, divide that by two, you get 5, so one number is 5 and then add the three to the other 5, you get 8
The numbers are 5 & 8

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3 years ago

Which decimal is equivalent to 11/25

ANTONII [103]

0.44 is equivalent to 11/25 .......

3 0

3 years ago