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2 years ago

PLEASE HELP I NEED THIS BRAINLISEST AND 20 POINTS

Mathematics

1 answer:

Bingel [31]2 years ago

3 0

Answer:

SA = 18.2+10.4h

59.8yd²

Step-by-step explanation:

Surface area of a 3D shape is the sum of the areas of its faces. A rectangular prism is made of 2 rectangles that make the top and bottom, plus four equal, larger rectangles.

surface area = 2(small rectangles)+4(large rectangles)

surface area = 2(3.5*2.6)+4(2.6h)

SA = 18.2+10.4h

SA = 18.2+10.4(4)

SA = 18.2+41.6

SA = 59.8yd²

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The base of the pyramid is a square what is the surface area if the pyramids height is 4 feet in the area of the base is 36 ft.?

KATRIN_1 [288]

Answer:

96 ft²

Step-by-step explanation:

The general formula for the surface area of a pyramid is:

SA = $\frac{1}{2}$ pl + B, were p = the perimeter of the base, l = the slant height and B = the area of the base

Since the area of the base is 36 ft², then each side is √36, or 6 ft. The perimeter is the sum of all the sides, so 6 x 4 = 24 ft.

Given the overall height of the pyramid is 4 feet, you can use the Pythagorean Theorem (a² + b² = c²) to find the slant height (hypotenuse) of the pyramid. Using 3 feet for 'a' and 4 feet for 'b':

3² + 4² = c² or 9 + 16 = 25

25 = c² or c = 5

SA = $\frac{1}{2}$ (24)(5) + 36

SA = 60 + 36 = 96 ft²

8 0

3 years ago

Simplify this expression

pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

8 0

2 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$