A line segment has endpoints P(-1,5)and Q(5,2) find the coordinate of that trisect the segment
1 answer:
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Answer:
Area = 492.4 m²
Explanation:
The area of the triangle can be calculated using the side-angle-side method as follows:
Area = 0.5 * first side * second side * sin(angle included between these two sides)
This rule is illustrated in the attached image.
Now, we have:
AB = 40 m
BC = 25 m
angle B which is the angle included between AB and BC = 80 degrees
The given angle is included between the two given sides, therefore, we can apply the above rule to get the area.
Area of triangle = 0.5*40*25*sin(80)
Area of triangle = 492.4 m²
Hope this helps :)
Area = 492.4 m²
Explanation:
The area of the triangle can be calculated using the side-angle-side method as follows:
Area = 0.5 * first side * second side * sin(angle included between these two sides)
This rule is illustrated in the attached image.
Now, we have:
AB = 40 m
BC = 25 m
angle B which is the angle included between AB and BC = 80 degrees
The given angle is included between the two given sides, therefore, we can apply the above rule to get the area.
Area of triangle = 0.5*40*25*sin(80)
Area of triangle = 492.4 m²
Hope this helps :)