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3 years ago

Graph x < or = to -4.5 on the number line HELP ME PLS ASAP PLS PLZ PLS HELP

Mathematics

1 answer:

Liula [17]3 years ago

5 0

Answer:

it would be a closed circle and to the right

Step-by-step explanation:

I have a little tip whenever the greater or less than sign is underlined it will always be closed, and when x is greater than -4.5 all the numbers that are greater than -4.5 will be on the right side so that will be your answer.

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HELP FAST PLEASE!!!!!

lidiya [134]

Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.

$2 cot(\frac{-9\pi}{2}) = 2 cot(\frac{9\pi}{2})$ Incorrect step

Because as per even/odd identity,

Cot (-Θ) = - cot (Θ)

Hence

$2 cot (\frac{-9\pi}{2}) = - 2 cot (\frac{9\pi}{2})$

Now,

It could be written as

$-2 cot (\frac{9\pi}{2}) = -2 cot (\frac{\pi}{2})$

$-2 * 0$

Hence the answer is 0. : Answer

Hope it will help :)

3 0

3 years ago

Factor 6w^4 + w^3 -3w^2

Shtirlitz [24]

6w^4+w³-3w²=w²(6w²+w-3)
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3 years ago

Can someone please explain the steps to solve these questions.

Amiraneli [1.4K]

Alright! So to solve these questions, you need to find out the difference. You can use ratios to solve this. For example, question #25:

A class had 30 pupils at the beginning of this school term, but now has 5 more pupils. What is the percent of increase?

The question is basically asking how much 5 is in ratio to 30. So just divide 5 (the given amount) by 30 (the total amount). The answer is 0.16, or 16%

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3 years ago

I need help please...............

Arte-miy333 [17]

Answer:

I cant see the entire question

Step-by-step explanation:

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3 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago