The maximum pressure variations the human ear can withstand above and below atmospheric pressure is around 30 pa. the normal atmospheric pressure is around 101325 pa. hence the variation in the maximum pressure for human ear is very small as compared to the atmospheric pressure. if the ear is exposed to a pressure greater than this , it can cause permanent damage to the ear.
Well the heat that is needed to raise the temperature of 10g of water by 17oC is
Answer:
<em>The block moves at 1.25 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
![P=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=P%3Dm_1v_1%2Bm_2v_2)
If a collision occurs and the velocities change to v', the final momentum is:
![P'=m_1v'_1+m_2v'_2](https://tex.z-dn.net/?f=P%27%3Dm_1v%27_1%2Bm_2v%27_2)
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
![m_1v_1+m_2v_2=m_1v'_1+m_2v'_2](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3Dm_1v%27_1%2Bm_2v%27_2)
The bullet of m1=0.049 kg moves at v1=421 m/s. Then it strikes a wooden block of m2=4.7 kg originally at rest (v2=0).
After the collision, the bullet continues at v1'=301 m/s. The speed of the block can be calculated by solving for v2':
![\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27_2%3D%5Cfrac%7Bm_1v_1%2Bm_2v_2-m_1v%27_1%7D%7Bm_2%7D)
![\displaystyle v'_2=\frac{0.049*421+0-0.049*301}{4.7}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27_2%3D%5Cfrac%7B0.049%2A421%2B0-0.049%2A301%7D%7B4.7%7D)
Calculating:
![\displaystyle v'_2=\frac{5.88}{4.7}=1.25\ m/s](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27_2%3D%5Cfrac%7B5.88%7D%7B4.7%7D%3D1.25%5C%20m%2Fs)
The block moves at 1.25 m/s
Answer:
d = vi * t + ½ * a * t^2, a = -0.5
d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m
d6 = 20.8 * 6 – ½ * 0.5 * 6^2 = 106.8m
d6 – d5 = 15.3 m
Explanation:
Answer:
.5m per second to the west
Explanation:
distance divided by time