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Nina [5.8K]
3 years ago
10

A motorcycle has a constant acceleration of 3.49 m/s2. Both the velocity and acceleration of the motorcycle point in the same di

rection. How much time is required for the motorcycle to change its speed from (a)29.0 to 39.0 m/s, and (b)59.0 to 69.0 m/s?
Physics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

(a)2.865 s

(b)2.865 s

Explanation:

We are given that

Acceleration,a=3.49 m/s^2

a.Initial speed,u=29 m/s

Final speed,v=39 m/s

We know that

t=\frac{v-u}{a}

Using the formula

t=\frac{39-29}{3.49}=2.865 s

b.Initial speed,u=59 m/s

Final speed,v=69 m/s

Again using the formula

t=\frac{69-59}{3.49}=2.865 s

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Anni [7]
Can u show the problem ?
Acceleration= the rate and change of an object also cars go fast so I think it would be positive acceleration
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3 years ago
How might you describe the mathematical procedure of finding the displacement when an object travels in two opposite directions?
levacccp [35]
Displacement is a vector quantity. So, you incorporate the vector calculations when you try to determine the resultant vector. This is the shortest path from the starting point to the endpoint. If they are moving on one axis only, you use sign conventions. For motions moving to the left, use the negative sign. If it's moving to the right, then use the positive sign. Now, it the object moves 2 km to the left, and 2 km also to the right, the displacement is zero.

Displacement = 2 km - 2km = 0

Generally, the equation is:
<span>Displacement = Distance of motion to the right - Distance of motion to the left</span>
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3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
2 years ago
What is the speed of sound at sea level?
svetlana [45]
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3 years ago
A person lifts a 25 kg box of old sports equipment at an angle of 75 degrees to the vertical to a shelf 2.6 meters above. How mu
kogti [31]

Answer:

164.87 J

Explanation:

From the question,

Work done (W) = mghcosθ........................ Equation 1

Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical

Given: m = 25 kg, h = 2.6 meters, θ = 75°.

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Substitute these value into equation 1

W = 25×9.8×2.6×cos75°

W = 164.87 J.

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