Question

A motorcycle has a constant acceleration of 3.49 m/s2. Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)29.0 to 39.0 m/s, and (b)59.0 to 69.0 m/s?

Answer 1

Answer:

(a)2.865 s

(b)2.865 s

Explanation:

We are given that

Acceleration,a=$3.49 m/s^2$

a.Initial speed,u=29 m/s

Final speed,v=39 m/s

We know that

$t=\frac{v-u}{a}$

Using the formula

$t=\frac{39-29}{3.49}=2.865 s$

b.Initial speed,u=59 m/s

Final speed,v=69 m/s

Again using the formula

$t=\frac{69-59}{3.49}=2.865 s$