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Dmitry [639]
3 years ago
10

If you throw a ball at 35° and 10 m/s what is the horizontal component of velocity

Physics
1 answer:
wariber [46]3 years ago
3 0

Answer:

8.2 m/s

Explanation:

The horizontal component of the velocity is given by:

v_x = v cos \theta

where

v = 10 m/s is the magnitude of the velocity

\theta=35^{\circ} is the angle at which the ball has been thrown, with respect to the horizontal

Substituting the values into the equation, we get

v_x=(10 m/s)(cos 35^{\circ})=8.2 m/s

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