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3 years ago

If you were on a ship at sea, and a tsunami passed under your ship, what would probably be your reaction? explain.

1 answer:

swat323 years ago

6 0

<span>Extremely powerful single waves have no effect on ships at sea since the depth of water allows the energy to be distributed over hundreds and thousands of feet. In deep water, the bigger the wave, the faster it moves and the slower the surface changes height. As the wave gets into shallow waters, it slows down and can start to pile up to large heights.</span>

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8. While taking a measurement, Ajay put the 2nd mark of the scale to the edge of the line and the mark that pointed to the end o

Leni [432]

Answer:

The length of line is 78 cm or 0.78 m.

Explanation:

initial reading 2 mark

final reading 80 cm

The length of the line

= final reading - initial reading

= 80 - 2

= 78 cm

1 cm = 0.01 m

So, 78 cm = 0.78 m

4 0

3 years ago

Why is it better to use the metric system, rather than the English system, in scientific measurement?

fiasKO [112]

A. The English system uses one unit for each category of measurement.

4 0

3 years ago

Read 2 more answers

A ball is thrown horizontally from the top of a building 22.3 m high. The ball strikes the ground at a point 127 m from the base

DochEvi [55]

Answer:

t = 2.13 s

Explanation:

given,

height of the building = 22.3 m

horizontal distance = 127 m

acceleration due to gravity = 9.8 m/s²

time for which ball is in motion = ?

using equation of motion

$s = u t + \dfrac{1}{2}gt^2$

initial velocity is zero

$s = \dfrac{1}{2}gt^2$

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 22.3}{9.8}}$

t = √4.551

t = 2.13 s

8 0

3 years ago

Two observers are 300 ft apart on opposite sides of a flagpole. The angles of elevation from the observers to the top of the pol

valentina_108 [34]

Answer:

h = 48.077 ft

Explanation:

given,

distance between two observer = 300 ft

angle of elevation to top pole = 16° and 20°

height of the flagpole = ?

now,

Let h be the height of the flagpole

Let x be the distance of the pole

$tan 16^0 = \dfrac{h}{x}$

$x =\dfrac{h}{tan 16^0}$

now,

again applying

$tan 20^0 = \dfrac{h}{300-x}$

$300-x=\dfrac{h}{tan 20^0}$

$300-3.49 h=2.75 h$

$6.24h = 300$

h = 48.077 ft

3 0

3 years ago

Two metal balls are the same size, but one weighs twice as much as the other. The balls are dropped from the top of a two story

seropon [69]

The time taken by the metal balls of the same size but different weight, to reach the ground will be the same.

Reason behind:

Two metal balls are the same size, but one weighs twice as much as the other. The balls are dropped from the top of a two-story building at the same instant of time. It is required to find the time taken by the balls to reach the ground.

In free fall, all objects experience the same acceleration owing to gravity when they are close to the earth.

$g=9.8 \text{ m/s}^2$ is the measure of gravitational acceleration.

Because of this, the two metal balls are the same size but have different masses. The air resistance for both balls will be the same due to their similar sizes. Let, g' be the acceleration in the presence of air resistance. The balls are both discharged at once.

From a height of h, both balls descend due to gravity G'.

Therefore, the time taken by both balls is:

$\begin{aligned}&s=u t+\frac{1}{2} g t^{2} \\&u=0, s=h \\&t=\sqrt{\frac{2 h}{g}}\end{aligned}$

Therefore, the time is independent of mass. Thus the time taken by both the balls, will be about the same.

Learn more about time taken by metal ball to reach the ground here,

brainly.com/question/22719691

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4 0

2 years ago