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3 years ago

If you were on a ship at sea, and a tsunami passed under your ship, what would probably be your reaction? explain.

1 answer:

swat323 years ago

6 0

Extremely powerful single waves have no effect on ships at sea since the depth of water allows the energy to be distributed over hundreds and thousands of feet. In deep water, the bigger the wave, the faster it moves and the slower the surface changes height. As the wave gets into shallow waters, it slows down and can start to pile up to large heights.

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A rock containing valuable minerals that can be mined is called

pav-90 [236]

I think, C. An ore. Sorry if wrong

8 0

4 years ago

Read 2 more answers

El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La

allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

$\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta$

En donde:

$\omega_{f}$ : es la velocidad angular final = 2000 rpm = 209,4 rad/s

$\omega_{0}$ : es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.

Resolviendo la ecuación (1) para α, tenemos:

$\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}$

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.

b) El tiempo transcurrido se puede encontrar como sigue:

$\omega_{f} = \omega_{0} + \alpha t$

Resolviendo para t, tenemos:

$t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s$

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0

3 years ago

Drivers a and b travel west from boston. driver a leaves three hours earlier traveling at a constant speed of 68mph. driver b fo

Elza [17]

We can answer this using one of the equations of linear motion:

v = d / t

where:

v = velocity

d = distance

t = time

In the problem, we are asked to find for the time in which Driver B will catch up to Driver A. Therefore, find the time when dA = dB. Rearranging the equation and equation dA and dB will result in:

vA * tA = vB * tB ---> 1

It was given that:

vA = 68 mph

tA = tB + 3 (since person A was travelling 3 hours earlier)

vB = 85 mph

tB = unknown

Substituting into equation 1:

68 * (tB + 3) = 85 * tB

68 tB + 204 = 85 tB

tB = 12 hrs

Therefore driver B would catch up to driver A after 12 hrs.

5 0

3 years ago

How did rutherford’s experiment shape our current model of the atom?

marissa [1.9K]

Answer:

Explanation:

Before the Rutherford's model of the atom, the plum pudding model proposed by J.J Thomson through his experiment using the gas discharge tube was the prevalent structure of the atom known.

Through Thomson, it was widely and popularly believed that the atom is made up of a pool of negatively charged particles.

When Rutherford performed the Alpha scattering experiment using a thing gold foil, he observed that all the alpha particles passed through the thin gold foil and just a few of them were deflected back.

To explain this, the suggested the atomic or nuclear model of that atom in which an atom has a small positively charged center called nucleus where all the mass is concentrated.

Today, the suggestion that an atom is made up of nucleus is highly relevant and still consistent.

6 0

4 years ago

A 50 kg car is pushed so that it speeds up from 20 m/s to 50 m/s in 3 seconds. What is the force acting on the car?

egoroff_w [7]

Answer:

A. 500 N

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (50 m/s − 20 m/s) / 3 s

a = 10 m/s²

Force is mass times acceleration.

F = ma

F = (50 kg) (10 m/s²)

F = 500 N

3 0

3 years ago