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2 years ago

15

If you were on a ship at sea, and a tsunami passed under your ship, what would probably be your reaction? explain.

1 answer:

swat322 years ago

6 0

<span>Extremely powerful single waves have no effect on ships at sea since the depth of water allows the energy to be distributed over hundreds and thousands of feet. In deep water, the bigger the wave, the faster it moves and the slower the surface changes height. As the wave gets into shallow waters, it slows down and can start to pile up to large heights.</span>

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Natalie accelerate her skateboard along a straight path from 0 m/s to 4.0 m/s in 2.5 s. find her average acceleration

Vikentia [17]

Acceleration=(speed end - speed start)/ time
Data:
speed end=4 m/s
speed start=0 m/s
time=2.5 s

acceleration=(4 m/s - 0 m/s)/2.5 s=1.6 m/s²

Answer: the acceleration would be 1.6 m/s²

8 0

3 years ago

Just like energy is <br> matter is lost through an ecosystem

Novosadov [1.4K]

Yes energy is reduced

7 0

2 years ago

Read 2 more answers

Nutka1998 [239]

Answer:

E = 3600 J

Explanation:

Given that,

Voltage, V = 115 V

Power of electric bulb, P = 60 W

We need to find the electric energy used in 1 minute. The electric energy use is given by :

$E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J$

Hence, the electrical energy is 3600 J.

8 0

3 years ago

A large container is pulled 20 meters with 40 newtons of force. The power exerted is 64 watts. How long did it take to move the

Usimov [2.4K]

A.(20*40)/64=12.5 hope i helped

3 0

3 years ago

A sphere of plastic of radius = .100 m is completely immersed in water. The density of the plastic is 600 kg/m3. Since the plast

tekilochka [14]

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

$F = ma \rightarrow mg$

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

$\rho = \frac{m}{V} \rightarrow m = \rho V$

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

$F = \rho V g$

Since the difference between the two forces gives us the total Force then we have to

$F_T = F_w - F_p$

Where

$F_w =$ Force of the water

$F_p$ = Force of plastic

Therefore with the values for this force we have,

$F_T = \rho_w Vg - \rho_p Vg$

$F_T = Vg(\rho_w - \rho_p)$

$F_T = (\frac{4}{3} \pi r^3) g(\rho_w - \rho_p)$

$F_T = (\frac{4}{3} \pi (0.1)^3) (9.8)(1000 - 600)$

$F_T = 16.412 N$

Therefore the tension in the thread is 16.412N

3 0

3 years ago