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2 years ago

An angle measures 3.8° more than the measure of its complementary angle. What is the measure of each angle?

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

Answer: 41.2 degrees

Step-by-step explanation:

Complementary angles are angles that add to 90 degrees, so if they were equal, they would be 45 and 45, but since one is 3.8 more, it is 45+3.8 = 48.8 and the other, to add to 90 degrees is 90-48.8 = 41.2

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Mr. Walker asked his students to use the associative property to find an expression that is equivalent to (13 + 15 + 20) + (20 +

pychu [463]

I got it as 4 when calculating all have the same number which is 133

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2 years ago

On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.

Reil [10]

9514 1404 393

Answer:

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

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Only graph A matches these points.

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3 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

3 years ago

Read 2 more answers

Fund the equation of the line that passes through the points (1,2) and (3,12).

aalyn [17]

Answer:

y=5x-3

Step-by-step explanation:

slope is 5, plug in (1,2) for x and y to find b

8 0

3 years ago

What is the average rate of change of the line whose equation is:

dedylja [7]

Answer:

Rate of change = -12

Step-by-step explanation:

y − 3 = −12(x + 4)

Expanding, we have;

y - 3 = -12x - 48

y = -12x - 48 + 3

y = -12x - 45

Now, formula for rate of change is;

Rate of change = (y(x + h) - y)/h

y(x + h) is; y = -12(x + h) - 45

This gives;

Rate of change = (-12(x + h) - 45 + 12x + 45)/h

Rate of change = (-12x - 12h - 45 + 12x + 45)/h

Rate of change = -12h/h

Rate of change = -12

3 0

3 years ago