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bulgar [2K]
3 years ago
13

Identify the effect on the graph of replacing f(x) by A f(x)

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

Required

Effect of replacing f(x) with f(x - h)

f(x) is represented as: (x,y)

While

f(x - h) is represented as (x - h, y)

Notice the difference in both is that, the x value in f(x - h) is reduced by a constant h while the y value remain unchanged.

This means that the graph of f(x) will shift horizontally (i.e. along the x-axis) to the left by h units

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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0
3 years ago
What are the values of the function y=-2 x-4 for x=0,1,2,3
iragen [17]

Answer:

read description

Step-by-step explanation:

y=-2(0)-4    ANSWER: y=-4

y=-2(1)-4     ANSWER: y=-6

y=-2(2)-4    ANSWER: y=-8

y=-2(3)-4    ANSWER: y=-10

7 0
3 years ago
The money raised By $15 candy is approximately What percent of The total money raised from The candy sale
Monica [59]
Can you explain it a bit more?
7 0
3 years ago
Read 2 more answers
the taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km,
Olegator [25]

Answer:

255

Step-by-step explanation:

total cost paid = fixed cost + total variable cost

total variable cost = distance travelled x variable cost per unit

two equations can be derived from the question

a + 10b = 105  equation 1

a + 15b = 155   equation 2

a = fixed cost

b =  variable cost per unit

Subtract equation 1 from 2

5b = 50

b = 10

Substitute for b in equation 1

a + 10(10) = 105

a = 105 - 100 = 5

a = 5

cost of travelling a distance of 25km

5 + 10(25) = 255

3 0
3 years ago
Please help i cant seem to figure this out
Ahat [919]

Answer:

117649

Step-by-step explanation:

7 to the power of 2 is 49 then bc its in () do 49 to the power of 3 = 117649

8 0
3 years ago
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