Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then
≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2±
where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704±
≈ -0.171 ±0.237 that is (−0.408, 0.066)
Answer:
read description
Step-by-step explanation:
y=-2(0)-4 ANSWER: y=-4
y=-2(1)-4 ANSWER: y=-6
y=-2(2)-4 ANSWER: y=-8
y=-2(3)-4 ANSWER: y=-10
Answer:
255
Step-by-step explanation:
total cost paid = fixed cost + total variable cost
total variable cost = distance travelled x variable cost per unit
two equations can be derived from the question
a + 10b = 105 equation 1
a + 15b = 155 equation 2
a = fixed cost
b = variable cost per unit
Subtract equation 1 from 2
5b = 50
b = 10
Substitute for b in equation 1
a + 10(10) = 105
a = 105 - 100 = 5
a = 5
cost of travelling a distance of 25km
5 + 10(25) = 255
Answer:
117649
Step-by-step explanation:
7 to the power of 2 is 49 then bc its in () do 49 to the power of 3 = 117649