Answer:
3xy² - 14y²
Step-by-step explanation:
I hope that this is the problem
- x²y + [ - (x²y - 2xy² + y²) + (xy² - 3y² + x²y)] - (10y² - x²y)
= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y
Now combine like terms in the [ ].
= - x²y + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y
= - x²y + [ 0 + 3xy² - 4y²] - 10y² + x²y
= - x²y + 3xy² - 4y² -10y² + x²y Now combine like terms
= (-x²y + x²y) + 3xy² + (-4y² - 10y²)
= 0 + 3xy² - 14y²
= 3xy² - 14y² or y²(3x - 14)
<u>Answer:</u>
3%
<u>Step-by-step explanation:</u>
We are given the data of number of cars observed waiting in line at the beginning of 2 minute intervals between 3 and 5 p.m. on Friday.
We are to find the probability (in percent) that there is no one in line.
Sum of frequencies = 2 + 9 + 16 + 12 + 8 + 6 + 4 + 2 + 1 = 60
Frequency of no car in line = 2
P (no car in line) = 2 / 60 × 100 = 3.3% ≈ 3%
Answer:
ah
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
Applying the Pythagoras Theorem
In this problem we have that
substitute
Answer: x= -3 + 2
or -3 -2 
Step-by-step explanation:
First you want to get the quadratic formula
in this case a=1 b=6 and c=1
plug it in and solve the equations
(sorry don't know how to put in equations here)
