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miv72 [106K]
3 years ago
13

Which algebraic expression represents the phrase "two times the quantity of a number minus 12"?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
The answer to the question is 2y-12
Mrac [35]3 years ago
6 0
The answer to the expression is 2y-12
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Which best describes the solution to 4-7
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Answer:

-3.

Step-by-step explanation:

It will be a negative number because you're taking 7 away from 4. You can do 7-4 and it will equal 3, but you flip it, and it will be -3.

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What is the image of the point (3,4) after a rotation of 90 degree counterclockwise about the origin
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(- 4, 3 )

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3 years ago
Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe
Dimas [21]

Answer:

The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 6.4

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

So

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 72.3}{6.4}

X - 72.3 = 1.405*6.4

X = 81.29

The minumum numeric grade you have to earn to obtain an A is 81.29.

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3 years ago
Find the value of t in the equation t+5+3t=1
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T is _1. I can show you how to do it, but I have more people to help
7 0
4 years ago
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