$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$

5 0

3 years ago

PLEASE HELP ASAP!!!

Elan Coil [88]

Answer:

The number is 5

Step-by-step explanation:

6+3n = 5n-4

Subtract 3n from each side

6+3n-3n = 5n-3n-4

6 = 2n-4

Add 4 to each side

6+4 = 2n-4+4

10= 2n

Divide by 2

10/2 =2n/2

5=n

6 0

3 years ago

Calculator

AnnZ [28]

It is 20 Square feet

7 0

3 years ago

I NEED ANSWERS PLEAS HELP FOR SCIENCE ​

I NEED ANSWERS PLEAS HELP FOR SCIENCE