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klasskru [66]
3 years ago
6

Please help me i’ve been stuck on this one

Mathematics
1 answer:
marta [7]3 years ago
6 0
I think it’s the first answer AB and CD
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the size of a red blood cell is 0.000007m and that of a plant cell is 0.00001265m show that a red blood cell is half of a plant
Readme [11.4K]

ANSWER: The size of a red blood cell IS approximately half the size of a plant cell.

EXPLANATION:

<em>1. We divide the size of the plant cell by 2 to see if half of its size is the size of a red blood cell. </em>

\frac{0.00001265}{2} = 0.000006325 m

Therefore, half of a plant cell's size is 0.000006325 m.

<em>2. We now compare the size of half of the plant cell to the size of the red blood cell.</em>

0.000006325 m and 0.000007 m are very close in size; therefore, the size of a red blood cell IS approximately half of a plant cell.

8 0
3 years ago
Solve by graphing <br><br> u=v and 6u=2v-24
Vadim26 [7]

Answer:

u=-6 \\ \\ v=-6

Step-by-step explanation:

In this exercise, we have two equations, namely:

u=v \ and \ 6u=2v-24

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

u=y \\ \\ v=x

Then:

\left\{ \begin{array}{c}y=x\\6y=2x-24\end{array}\right.

So here we have two lines.

The first one is:

\boxed{y=x}

This line passes through the origin and has a slope m=1

The second one is:

6y=2x-24 \\ \\ \therefore y=\frac{2x-24}{6} \\ \\ \therefore \boxed{y=\frac{1}{3}x-4}

This line has a slope m=\frac{1}{3} and cuts the y-axis at b=-4

By using graph tools, we get the graph shown below, then:

x=-6 \\ \\ y=-6 \\ \\ \\ Since \ u=y \ and \ v=x, then: \\ \\ u=-6 \\ \\ v=-6

8 0
3 years ago
How many hours in 90 minutes
irakobra [83]
1.5 hours is in 90 minutes
6 0
3 years ago
Read 2 more answers
Solve the following system of equations:
ICE Princess25 [194]

Answer:

(-1,-1)

thats where they intersect

and thats the answer

Step-by-step explanation:

plz give brainlyest

8 0
3 years ago
Read 2 more answers
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi
Margaret [11]

Answer:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=26Kg

Step-by-step explanation:

Data

Brine a (Ba)

V_{Ba}=5\frac{Lt}{min}\\  Concentration(Bca)=0.05\frac{Kg}{Lt}

Brine b (Bb)

V_{Bb}=10\frac{Lt}{min}\\  Concentration(Bcb)=0.04\frac{Kg}{Lt}

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}

Finally:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=0.65\frac{Kg}{min}(40min)=26Kg

being y(t) the amount of salt (y) per unit of time (t)

5 0
3 years ago
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