Answer:
(a) $4250,
(b) $5225.
Step-by-step explanation:
Let n represent number of months.
We have been given that John saves $3500 the first month and every month later decreases it by $75.
First of all, we will find formula of John's savings in n months using arithmetic progression, where, 1st term is 3500 and common difference is 75.
, where,
n = Number of terms in a sequence,
d = Common difference.
(a) To find John's savings in 11 months, we will substitute in above formula.
Therefore, John would have saved $4250 in the 11th month.
(b) To find John's savings after 2 years, we will substitute in above formula.
Therefore, John would have saved $5225 in 2 years.
I believe it is 11/2
slope is the rise over the run so you plot the points on a graph and count the spaces between the two going up and then over to the side
going up you’d get 11
going to the right you’d get 2
Answer:
Step-by-step explanation:
its 71 my dude :)
X^-3
Anything to the power of 0 is 1 so
X^-3/1= X^-3
Answer:
12
Step-by-step explanation:
Im going to divide this up to make it easier
first im going to do the triangle on top which we need the formula for that which would be
(4*2) / 2 which is( base * height )/2 then 4*2 = 8 /2 = 4
then ill deal with the rectangle just below that triangle
which is 3*2 which is 6
then last is triangle which is 2*2 which is 4 / 2 so 2
then add all together
4 + 6 + 2 = 12