I need help my self lol XD sorryyyyyyyyy88898
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that

Putting
, we get



Therefore, the measure of angle RQP is 33 degrees.
Answer:
y = -4x + 2
Step-by-step explanation:
y = mx + b ( slope-intercept)
1. Find Slope:

Lets name 2 as y2 and 10 as y1. And 0 as x2 and 2 as x1.
=
= -4
m/slope = -4
2. Find y-intercept:

2 = -4(0) + b
= 2 = b
Y-intercept/b = 2
3. Put into slope-intercept form:
y = mx + b
= y = -4x + 2
Hope that helps! :D
Answer:
false i think? and true
Step-by-step explanation:
Answer:
,
,
, 
Step-by-step explanation:
i got it right