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pav-90 [236]
3 years ago
15

The perimeter of a rectangle can be found using the formula P = 4 s . True or False

Mathematics
2 answers:
Minchanka [31]3 years ago
6 0

Answer:

{ \underline{ \sf{true}}}

mina [271]3 years ago
5 0

Answer:

The perimeter of a rectangle can be calculated by adding both lengths, and both widths

Step-by-step explanation:

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If 4 is added to double the number n, the result is the same as
svlad2 [7]
I think it’s A because 4*2 is 8 and if n were quadrupled it would be 2
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3 years ago
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The amount of simple interest earned I, on an investment over a fixed amount of time ????, is jointly proportional to the princi
AleksAgata [21]

Answer:$920

Step-by-step explanation:

Since the variation is joint, I=KPr where k is the constant of proportionality.

Plugging in the values of I=$375, P=$1500 and r=5% in the equation I=KPr, the value of k can be calculated. Hence, the formula connecting the three quantities (I,P and r) can be generated.

375 = K (1500×5)

Making k the subject of change,

K = 375/(1500×5)

K=1/20

Formula connecting the three quantities :I =Pr/20

when P=$2300, r=8%,

I = (2300×8)/20

I = $920

3 0
3 years ago
Z=6x-y solve for x i need this for aleks
postnew [5]

Answer:

(z+y)/6=x

Step-by-step explanation:

Solve for x: z=6x-y

Add y on both sides: z+y=6x

Divide by 6 on both sides (z+y)/6=x

Hope this helps plz mark brainliest if correct :D

8 0
3 years ago
Where does the helix r(t) = cos(πt), sin(πt), t intersect the paraboloid z = x2 + y2? (x, y, z) = What is the angle of intersect
Colt1911 [192]

Answer:

Intersection at (-1, 0, 1).

Angle 0.6 radians

Step-by-step explanation:

The helix r(t) = (cos(πt), sin(πt), t) intersects the paraboloid  

z = x2 + y2 when the coordinates (x,y,z)=(cos(πt), sin(πt), t) of the helix satisfy the equation of the paraboloid. That is, when

\bf (cos(\pi t), sin(\pi t), t)

But  

\bf cos^2(\pi t)+sin^2(\pi t)=1

so, the helix intersects the paraboloid when t=1. This is the point

(cos(π), sin(π), 1) = (-1, 0, 1)

The angle of intersection between the helix and the paraboloid is the angle between the tangent vector to the curve and the tangent plane to the paraboloid.

The <em>tangent vector</em> to the helix in t=1 is

r'(t) when t=1

r'(t) = (-πsin(πt), πcos(πt), 1), hence

r'(1) = (0, -π, 1)

A normal vector to the tangent plane of the surface  

\bf z=x^2+y^2

at the point (-1, 0, 1) is given by

\bf (\frac{\partial f}{\partial x}(-1,0),\frac{\partial f}{\partial y}(-1,0),-1)

where

\bf f(x,y)=x^2+y^2

since

\bf \frac{\partial f}{\partial x}=2x,\;\frac{\partial f}{\partial y}=2y

so, a normal vector to the tangent plane is

(-2,0,-1)

Hence, <em>a vector in the same direction as the projection of the helix's tangent vector (0, -π, 1) onto the tangent plane </em>is given by

\bf (0,-\pi,1)-((0,-\pi,1)\bullet(-2,0,-1))(-2,0,1)=(0,-\pi,1)-(-2,0,1)=(2,-\pi,0)

The angle between the tangent vector to the curve and the tangent plane to the paraboloid equals the angle between the tangent vector to the curve and the vector we just found.  

But we now

\bf (2,-\pi,0)\bullet(0,-\pi,1)=\parallel(2,-\pi,0)\parallel\parallel(0,-\pi,1)\parallel cos\theta

where  

\bf \theta= angle between the tangent vector and its projection onto the tangent plane. So

\bf \pi^2=(\sqrt{4+\pi^2}\sqrt{\pi^2+1})cos\theta\rightarrow cos\theta=\frac{\pi^2}{\sqrt{4+\pi^2}\sqrt{\pi^2+1}}=0.8038

and

\bf \theta=arccos(0.8038)=0.6371\;radians

7 0
3 years ago
Five times the difference of a number and two is seven more than that number
lakkis [162]
5(x-2)=7+x would be your equation 
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3 years ago
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