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Stella [2.4K]
2 years ago
8

Solve 8 = 2^x + 4 x = −4 x = −1 x = 0 x = 7

Mathematics
1 answer:
TEA [102]2 years ago
8 0
None of these answers match up to the equation. The answer is 2. 2^2, 2x2=4
4+4=8
8=2^2+4
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Enter the values of h and I so that y=x2+6x+10 is in vertex form<br> Y=(x+__)^2+___
DiKsa [7]

Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}

3 0
3 years ago
Please help asap :( This is my "Final grade" My Teacher wants a full explanation included ! on how i got the answer. )
Mrac [35]

If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)

The total volume of the ball will be;

= Total volume - Volume of hollow part

= 4/3πr³ - 4/3πr³

= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³

= 4 × 3.14 × 9 - 4/3 × 3.14 × 8

= 113.04 - 33.52

= 79.52

If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;

= 79.52 × 3.25

= 258.44 g

Now, if there are 8 spheres in one box, the weight if box will be;

= 258.44 × 8

= 2,067.52 g

_____________________________

Ahh! Finally done with this, if you have any doubt just do ask me :)

3 0
3 years ago
X = [ ? ]<br><br> BRAINLEST to whoever is right!!
Nataly_w [17]

Answer:

x=125

Step-by-step explanation:

all angles of a triangle add up to 180 degrees.

30+25=55

180-55=125

3 0
2 years ago
I need some help? I can't quite figure it out lol
tensa zangetsu [6.8K]
1) <span>95.65217391%
3)</span><span>-61.25%
5)</span><span>-29.54545454%</span>
4 0
3 years ago
Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of
IrinaK [193]
Recall that the characteristic polynomial of a 2x2 matrix \mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix} is

\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)

but \det(\mathbf A)=ad-bc and \mathrm{tr}(\mathbf A)=a+d, so the characteristic polynomial for \mathbf A is

\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

\lambda^2-15\lambda+50

and the eigenvalues are those \lambda for which the characteristic polynomial evaluates to 0.

\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10
5 0
2 years ago
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