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Allisa [31]
2 years ago
10

Need help with theses plz

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
8 0

Answer:

7. x=19      2x=38

8.x=23     3x=69

9.x=12      (50-2)/4=12

10.x=15     (31-1)/2

11.x=16      (84-4)/5

12.x=27     (55-1)/2

Step-by-step explanation:

if 2 angles are opposite, it's the same

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Need help on this pls
aliya0001 [1]
The answer to the question is A
4 0
2 years ago
Find A and B if the graph of Ax + By = 12 passes through (2,1) and is parallel to the graph of 2x - 7y = 3
Ivenika [448]

Answer:

24-21

Step-by-step explanation:

2×12=24 7×3=21 I started from 2×2 towards 2×12 when I got the answer and I started 7×1 towards 7×3

4 0
2 years ago
Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
Solve the equation -15=a/5 <br> A=-3<br> A=-20<br> A=-10<br> A=-75
agasfer [191]

To solve any equation, you do whatever you need to do 
to wind up with the unknown quantity all alone on one side.
BUT ... whatever you do to one side of the equation, you must
also do to the other side.

Here, we have the
he original equation:           -15  =  a/5

Multiply each side by 5 :     -75  =  a

and bada-bing, THERE's the solution !
4 0
3 years ago
X4y(4) = yx2(13), calculate (x+y)2
Delicious77 [7]

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

"X4y(4) = yx2(13)"


Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


3 0
3 years ago
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