Divide 14 by 6 and there is your answer with the unit of m
It is A. a refrigerator cause a alternating current is current that doesn't stop and the refrigerator is plug into the wall.
I'm not sure but for the first one, if there were more electrons than protons that would mean the object would have a positive charge so you could put another object that is positively charged near it, to see if it would attract and if it would it would mean it's negatively charged and if it wouldn't it would mean it's positively charged. (not sure)
for the second one, after you've rubbed the balloon oh hair, the electrons from your hair have transferred onto the balloon, meaning that the balloon is now negatively charged. because the wall is neutral, it means that it has the SAME number of both protons and electrons ( positive and negative charges cancel out to create a neutral charge). because the protons are positively charged, and the balloon is negatively charged, the two objects will attract because opposite charges attract. this happens because of static electricity.
hope this helps :)
<span>The gain in potential energy is 600*2 = 1200 J, and this is the minimum required work that would be required in a frictionless situation. The work that actually has to be done is F*X = 300*5 = 1500 J. The efficiency is therefore 1200/1500 = 80%</span>
Answer:
<h2>
0.2 m/s²</h2>
Explanation:
Given,
Mass ( m ) = 10 kg
Force ( f ) = 2 Newtons
Acceleration ( a ) = ?
Now, let's find the acceleration :
We know that,
![f = ma](https://tex.z-dn.net/?f=f%20%3D%20ma)
Plug the values
![2 = 10a](https://tex.z-dn.net/?f=2%20%3D%2010a)
Swap the sides of the equation
![10a = 2](https://tex.z-dn.net/?f=10a%20%3D%202)
Divide both sides of the equation by 10
![\frac{10a}{10} = \frac{2}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B10a%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B10%7D%20)
Calculate
![a = 0.2 \: {metre \: per \: second \: }^{2}](https://tex.z-dn.net/?f=a%20%3D%200.2%20%5C%3A%20%20%7Bmetre%20%5C%3A%20per%20%5C%3A%20second%20%5C%3A%20%7D%5E%7B2%7D%20)
Hope this helps...
Best regards!!