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antiseptic1488 [7]
4 years ago
10

A sprinter runs 200m west and 100 m east her displacement is

Physics
2 answers:
kykrilka [37]4 years ago
8 0
100m so you will subtract 100m from 200m. and you will get your answer 200m-100m=100m
Margaret [11]4 years ago
7 0

Her displacement is 100m West.

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earnstyle [38]

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3 years ago
A 260-kg glider is being pulled by a 1,940-kg jet along a horizontal runway with an acceleration of a= 2.20 m/s^2 to the right.
lisov135 [29]

Answer:

a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

Explanation:

a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:

Jet

\Sigma F = F - T = m_{J}\cdot a (1)

Glider

\Sigma F = T = m_{G}\cdot a (2)

Where:

F - Thrust of jet engines, measured in newtons.

T - Tension in the cable connecting the jet and glider, measured in newtons.

m_{G}, m_{J} - Masses of the glider and the jet, measured in kilograms.

a - Acceleration of the glider-jet system, measured in meters per square second.

If we know that m_{G} = 260\,kg, m_{J} = 1,940\,kg and a = 2.20\,\frac{m}{s^{2}}, then the solution of this system of equations:

By (2):

T = (260\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

T = 572\,N

By (1):

F = T+m_{J}\cdot a

F = 572\,N+(1,940\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

F = 4840\,N

The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

7 0
3 years ago
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We can get the gravity force as follows:

Fg = (mb +mhe) g  

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Valentin [98]

Answer:

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3 years ago
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