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zhannawk [14.2K]
3 years ago
5

Which compound is held together by the electrostatic force between two ions?

Physics
1 answer:
Paladinen [302]3 years ago
5 0

D. MgF₂

Explanation:

The compound that is held together by the electrostatic force between two ions is MgF₂.

Electrostatic force of attraction is exhibited primarily and only in ionic compounds.

In this type of bond;

  • A metallic atom such as Mg will lose two of its valence electrons to form Mg²⁺
  • Two non-metal ion that is highly electronegative such as "F" will gain the two electrons because they require an electron each to have a perfect octet.
  • Two ions are now formed.
  • In the vicinity of one another, they attract with an electrostatic force.
  • This is why our answer is MgF₂.
  • Electrostatic force occurs in ionic/electrovalent compounds

learn more:

Ionic bond brainly.com/question/10826758

#learnwithBrainly

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If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Firdavs [7]

The new cross sectional area and tensile stress is mathematically given as

A=4.8*10^{-4}m^2

X=14:100

<h3>Cross sectional area and stress on the femur</h3>

Question Parameters:

To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4%

we scale this man up by a factor of 10 in all dimensions

that a 70 kg person has a femur with a cross-section area

a)

Generally the New cross sectional area  is mathematically given as

100A=100*4.8*10^{-4}

A=4.8*10^{-4}m^2

b)

From the initial statement we see that  the fraction of the tensile strength is the stress on the femur  and will be

X=\frac{14}{100}

X=14$

X=14:100

For more information on fraction

brainly.com/question/1301963

Complete Question

Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared to 16% for an elephant. To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4% of the bone's tensile strength. Suppose we scale this man up by a factor of 10 in all dimensions, keeping the same body proportions. (Assume that a 70 kg person has a femur with a cross-section area (of the cortical bone) of 4.8 x 10-4m², a typical value.)

Part A

Both the inside and outside diameter of the femur, the region of cortical bone, will increase by a factor of 10. What will be the new cross-section area? Express your answer using two significant figures.

Part B

If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?

8 0
2 years ago
A 1.2-kg mass is projected from ground level with a velocity of 30 m/s at some unknown angle above the horizontal. A short time
Dmitriy789 [7]

Answer:

K_f = 351.84 J

Explanation:

Using the conservation of energy K:

E_i = E_f

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\frac{1}{2}mv^2 = K_f + mgh

where m is the mass, v the initial velocity, K_f is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.

Then, replacing values, we get:

\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)

solving for K_f:

K_f = 351.84 J

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3 years ago
What term described the capability to prevent one participant in an electronic transaction from denying it performed an action?
vampirchik [111]

Answer:

Plausible deniability.

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How can force-time and force-displacement graphs be used to find the impulse or work done?
balandron [24]

Answer:

A. Area under force-time graph & Area under force-displacement graph

Explanation:

To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.

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When we plot a graph of force and time, the area under it is the impulse.

When a graph of force and displacement is plotted, the area under is the work done.

7 0
3 years ago
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