1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kari74 [83]
3 years ago
9

Contrasting the Doppler effect with shock waves, the one that requires the faster source is?

Physics
2 answers:
MAXImum [283]3 years ago
6 0

I think shock waves require more speed they travel at the speed of sound

WITCHER [35]3 years ago
5 0

Answer:

Shock waves

Explanation:

The Doppler effect is well noticed at moments where the speed of the source is going slower than the speed of the waves. E.g. the change in apparent frequency of the sound of a train horn. As the train nears the observer, the blast of its horn is observed at a high pitch and as the train accelerates further, the blast of its horn is observed at a low pitch.

A shock wave is observed if the source is going at an equal speed as or faster than the wave can go. When the origin of sound moves at an equal speed as sound, it results in the source being at the front edge of the waves that it forms at all times.

The attached image shows a snapshots in time of diverse wavefronts forned by an aircraft that is accelerating at an equal speed as sound. The circular lines represent compressional wavefronts of the sound waves. Notice that these circles are bunched up at the front of the aircraft. This phenomenon is known as a shock wave. Shock waves are also produced if the aircraft moves faster than the speed of sound. If a moving source of sound moves faster than sound, the source will always be ahead of the waves that it produces. The diagram at the right depicts snapshots in time of a variety of wavefronts produced by an aircraft that is moving faster than sound. Note that the circular compressional wavefronts fall behind the faster moving aircraft (in actuality, these circles would be spheres).

You might be interested in
Two forces and are applied to an object whose mass is 13.3 kg. The larger force is . When both forces point due east, the object
ANEK [815]

Answer:

Explanation:

First, It's important to remember F = ma, and in this problem m = 13.3 kg

This can be reduced to a simple system of equations problem.  Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them.  So let's call them F1 and F2, with F1 arger than F2.  Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.  

Can you solve this system of equations seeing them like this, or do you need more help?

6 0
2 years ago
When a star goes from the main sequence to the red giant phase, it becomes larger rather than smaller. This is true because grav
GuDViN [60]
I believe this is electron degeneracy, because the star is essentially having too many reactions too fast and collapses in on itself eventually.
4 0
3 years ago
SHOW WORK
Helga [31]

Answer:

Follows are the solution to the given question:

Explanation:

For point a:

T= 2\pi \sqrt{\frac{m}{k}}\\\\k = \frac{4 \pi^2 m}{T^2}\\\\= \frac{4 \times (3.14)^2 \times 3}{2^2}\\\\=29.578 \ \frac{N}{m}\\\\

For Point b:

E=\frac{1}{2} m a^2 w^2\\\\

   =\frac{1}{2} \times m \times a^2 \times \frac{4\pi^2}{T^2}\\\\=\frac{1}{2} \times 3 \times (0.15)^2 \times \frac{4\times 3.14^2}{2^2}\\\\=0.332 \ J

For Point C:

V_{max}= a w

        = (0.15) \times \frac{2\pi}{T}\\\\= (0.15) \times \frac{2\times 3.14}{2}\\\\=0.471 \frac{m}{s}

For point D:

X= a \sin (wt+ \phi)\\\\0.91=0.15 \sin(\frac{2\pi}{T} \times t+\phi)\\\\0.91=0.15 \sin(\frac{2\times 3.14}{2} \times 0.5+\phi)\\\\0.60 = \sin(3.14 \times 0.5+\phi)\\\\0.60 = \sin(1.57+\phi)\\\\1.57 +\phi =\sin^{-1} 60^{\circ}\\\\1.57 +\phi = 36.86^{\circ}\\\\=35.29^{\circ}\\\\So, X=15 \sin(3.14t+35.29^{\circ}) \ cm

5 0
3 years ago
The number of neutrons is equal to the atomic number<br> O A True<br> B. False
jonny [76]

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number. Therefore, it is true!

6 0
3 years ago
Read 2 more answers
SCIENCE HELP! PLEASE HELP URGENT!
Nonamiya [84]
It is also tripled, there is a rule to everything, whatever you do to one thing, you do the exact thing to the other. Hope this solves it :)
6 0
2 years ago
Other questions:
  • Consider the following three statements: (i) For any electro-magnetic radiation, the product of the wavelength and the frequency
    5·2 answers
  • A car accelerates from 30 ft/s to 90 ft/ sec in 6 seconds
    9·1 answer
  • A force that results from charged particles is called?
    14·2 answers
  • What are the similarities in the 3 types of waves
    6·1 answer
  • HELP ME !!!! A.S.A.P!!!!! WILL BE MARKED AS BRAINLEST!!! 15 POINTS!!!!
    9·2 answers
  • If Jupiter were 10 times more massive, it would generate nuclear fusion in its core and be a star instead of a planet. If Jupite
    12·2 answers
  • Colossal Cave was formed years ago by underground running water. Today, it is the home to many animals, like bats. These interac
    7·1 answer
  • A roller coaster car starts at 6 m/s at the top of the hill at the 3 seconds latter at the bottom of the hill the roller coaster
    11·1 answer
  • PLZ Help Me I give you brainlist also NO LONKS OR I REPORT and Have a gr8 day my peeps
    5·1 answer
  • Why should you rotate food when thawing it 360 training?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!