A vertical stretch by a factor of 2 of F(x) = -2|x-2|+4 would result in the revised function G(x) = -4|x-2|+4. The vertex would stay in the same place (2,4).
To find the gradient of a line you use this equation: Rise / Run
I am assuming this is a graph where both the x and y-axis increase in value by one.
So first of all, you should draw out this graph.
Second, draw a point at each of the given coordinates.
Now, join these points by drawing a right angle triangle. Put simply, draw a line from the point (4, -7) down until it is on the same level as the point (2, -3), then draw a line across.
Finally, measure the length of both these sides and use them in the equation above.
Let's assume the rise (vertical line) and the run (horizontal line) are 5 and 8 respectively. We can do 5/8 to get a gradient which is 0.625.
Answer:
482
Step-by-step explanation:
We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

Where
is the first term,
is the nth term, and
is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do
, which is
, or the common difference. Since we have everything we need, it can be plugged into the equation:

So, the 61st term is 482.
I think it is 53 that’s what i would put if i were u
You can consider the triangle (as on in the picture) and apply to it composition of two transformations:
1. reflection about the line y=x to form ΔA'B'C' and translation 1 unit right and 5 units up to form ΔA''B''C'';
2. translation 1 unit right and 5 units up to form ΔA'B'C' and reflection about the line y=x to form ΔA''B''C''.
You can see that results are different.
On added picture blue colour responds to composition of transformations 1 and red colour to composition of transformations 2.