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diamong [38]
3 years ago
8

Consider a sphere with a volume of 36,000 π cubic centimeters.

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

30 cm

Step-by-step explanation:

Vol. of a sphere   (4/3) \pi  r^3=36000 \pi \\r^3=36000*3/4=27000\\r=30 cm\\

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In “Socialism vs. Capitalism: Which is the Moral System”, author C. Bradley Thompson refers to _____ as the only moral and just
frosja888 [35]

Answer:   B. Capitalism

Step-by-step explanation:

7 0
3 years ago
What is the surface area of the square pyramid? 30 m 18 m ות 36​
gayaneshka [121]

Answer:

the answer is 5100 im pretty sure.

Step-by-step explanation:

yes

4 0
3 years ago
6+5(9÷3)2 help answer it pls
lorasvet [3.4K]

Answer:

The answer should be 36, unless there is a typo

8 0
3 years ago
Read 2 more answers
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
3 years ago
Forty is 40% less than what number
kirza4 [7]

40 = n-.40n

40 =n(1-.4)

40 = n(.6

divide by .6 on each side

40/.6 =n

n=66 2/3



5 0
3 years ago
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