ANSWER FOR BRAINLIEST:

Mathematics

2 answers:

trapecia [35]3 years ago

7 0

Mean , median , and mode.

Vlada [557]3 years ago

3 0

Answer:

In statistics, the three most common measures of central tendency are the mean, median, and mode. Each of these measures calculates the location of the central point using a different method.

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H(n)=-4n-5<br> g(n)=n-1<br> Find h(g(n)) =

Delicious77 [7]

Answer:

h(g(n))=4n-9

Step-by-step explanation:

h(g(n))=4*g(n)-5 ( we replace n in the formule of h(n) by g(n).

h(g(n))=4(n-1)-5

h(g(n))=4n-4-5

h(g(n))=4n-9

Hope you understand it

3 0

3 years ago

Is 7/20 and 0.07 equivalent numbers

IceJOKER [234]

$\frac{7}{20}=0.35 \\ 
 \\ \frac{7}{100}=0.07 \\ 
 \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\$

7 0

4 years ago

Read 2 more answers

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval o

aleksklad [387]

Answer:

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

Step-by-step explanation:

Given that there is a continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers

Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely

Say if the interval is (a,b) P(X) = p the same for all places

Since total probability is 1,

we get integral of P(X)=p(b-a) =1

Or p= $\frac{1}{b-a}$

this is nothing but a uniform distribution continuous defined in the interval

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

8 0

3 years ago

Can someone help me please

dmitriy555 [2]

Answer:

Step-by-step explanation:

The rule with like bases is that when you multiply them you add their exponents.

$m^4*m^1=m^5$