1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
blondinia [14]
2 years ago
13

Which two equations are parallel?

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
5 0

Answer: The third option is correct.

Step-by-step explanation:

In order for two equations to be parallel, the equations' slopes must be the same.

You might be interested in
There are two functions that can be used to describe the percent of people 25 years and older who have completed at least high s
Korvikt [17]

Answer:

g(15)=93.8\%

see the explanation

Step-by-step explanation:

Let

x ----> the number of years since 2008,

g(x) ----> the percent of people 25 years and older who have completed at least high school

we know that

g(x)=0.008x^2+0.42x+87.5

so

For x=15 years since 2008

substitute

g(15)=0.008(15)^2+0.42(15)+87.5=93.8\%

That means

In the year 2023 (2008+15) the percent of people 25 and older completing at least high school will be 93.8%

5 0
3 years ago
Consider the original triangle and the enlargement,<br> 2 cm<br> 8 cm<br> 3 cm
LenKa [72]

Answer:

12 cm

Step-by-step explanation:

2x4=8

3x4=12

Thats why

4 0
3 years ago
In parallelogram JKLM if m
svetlana [45]

Answer:

155 degree

Step-by-step explanation:

x + 25 = 180 degree (sum of adjacent angles of a parallelogram are equal)

x = 180 - 25

x = 155 degree

4 0
2 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
Verizon [17]
A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}&#10;\\&#10;\\2.33=0.35\div \frac{0.85}{\sqrt{n}}=0.35\times \frac{\sqrt{n}}{0.85}

Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n

Divide both sides by 0.35:
1.9805/0.35 = √n

Square both sides:
(1.9805/0.35)² = n
32 ≈ n
8 0
3 years ago
To each of the fraction below find 3 fractions with denominators powers of 10 getting closer and closer to it and hence write it
g100num [7]

Solution:-1

\\ \sf\longmapsto \dfrac{4}{7}

\\ \sf\longmapsto \dfrac{5}{8}

\\ \sf\longmapsto \dfrac{2}{9}

Solution:-2

\\ \sf\longmapsto \dfrac{1}{11}

\\ \sf\longmapsto 0.09

7 0
3 years ago
Other questions:
  • -/2 points
    8·1 answer
  • the food stand at the zoo so 2514 lb of hamburger last month but average cost of a pound of hamburger is $2 Germany's estimates
    14·1 answer
  • How do I find the volume
    10·1 answer
  • Write an equation in slope intercept form for the line that passes through (3, 5) and is perpendicular to the line whose equatio
    15·1 answer
  • Maria, Hans, and Dan have a total of $95 in their wallets. Dan has 3 times what Hans has. Hans has $10 more than Maria. How much
    11·1 answer
  • Can someone help me with this one please? Also give me the steps. Thanks :)
    9·1 answer
  • 3 tens minus 3 tens 3 tenth
    5·1 answer
  • Tell whether the ratios form a proportion. 3/4 and 24/18​
    13·1 answer
  • What is the domain and range of d(x)=|x|-4
    14·1 answer
  • Today only, a suit is being sold at a 32% discount. The sale price is $323.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!