The compound's molecular formula is C6H6
Answer:
empirical formula = C3H7
molecular formula = C6H14
I think the answer is B. the sum of the enthalpy changes of the intermidiate reactions
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
? g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane
Answer:
2AlCl3 + 3H2SO4 → Al2(SO4)3 + 6HCl
Explanation: