Answer:
3
Explanation:
motion means movement, none of the others show movement
Answer:
Differences between Orbit and Orbitals
Orbit
An orbit is the simple planar representation of an electron.
It can be simply defined as the path that gets established in a circular motion by revolving the electron around the nucleus
The shape of molecules cannot be explained by an orbit as they are non-directional by nature.
An orbit that is well-defined goes against the Heisenberg principle.
Orbital
An orbital refers to the dimensional motion of an electron around the nucleus in a three-dimensional motion.
An orbital can simply be defined as the space or the region where the electron is likely to be found the most.
The shapes of the molecules can be found out as they are directional by nature.
An ideal orbital agrees with the theory of Heisenberg’s Principles.
Answer:
By using any one technique like boiling, distillation, condensation ,etc , one can be used to distinguish between a pure substance and a homogeneous mixture.
Explanation:
If the liquid is a pure substance, then it can not be separated by using physical means because all atoms of a pure substance show same properties.
But on the other hand, if there is homogeneous mixture, it can be separated by using techniques like boiling, distillation, condensation ,etc.
<u>Thus, using any of the one method listed above can be used to distinguish between a pure substance and a homogeneous mixture.</u>
Answer:
Empirical Formula = NH₄NO₃ (Ammonium Nitrate)
Solution:
Step 1: Calculate Moles of each Element;
Moles of N = %N ÷ At.Mass of N
Moles of N = 35.0 ÷ 14
Moles of N = 2.5 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 59.96 ÷ 16
Moles of O = 3.7475 mol
Moles of H = [100% - (%N + %O)] ÷ At.Mass of H
Moles of H = [100% - (35.0 + 59.96)] ÷ 1.008
Moles of H = [100% - 94.96] ÷ 1.008
Moles of H = 5.04 ÷ 1.008
Moles of H = 5 mol
Step 2: Find out mole ratio and simplify it;
N H O
2.5 5 3.7475
2.5/2.5 5/2.5 3.7475/2.5
1 2 1.5
Multiply Mole Ratio by 2,
2 4 3
Result:
Empirical Formula = N₂H₄O₃
Or,
Empirical Formula = NH₄NO₃
This empirical formula is also a Molecular Formula for Ammonium Nitrate a well known Fertilizer and often misused in the formation of Explosives.
