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3 years ago

Which formula represents a hydronium ion? (1) H3O+ (3) OH– (2) NH4+ (4) HCO3–

Chemistry

2 answers:

bearhunter [10]3 years ago

5 0

Answer : The correct option is, $H_3O^+$

Explanation:

The chemical formula of hydronium ion is, $H_3O^+$

It is formed by the protonation of water that means it is formed by the combination of $H^+$ ion with the water molecule. The hydronium ion is the positively charged molecule.

It is the simplest form of oxonium ion.

Or we can say that the hydronium ion is produced when an Arrhenius acid dissolves in water.

The reaction will be,

$H_2O+H^+\rightarrow H_3O^+$

Hence, the correct option is, $H_3O^+$

Zolol [24]3 years ago

4 0

The answer is (1) H3O+. OH- is called hydroxyl. HN4+ is called ammonium. HCO3- is called bicarbonate. Hydronium ion is the combination of H+ ion(hydrogen ion) and H2O(water molecule).

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mariarad [96]

Given:
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Required: percent by mass of each object

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M = 6.5 kg + 1.5 kg + 2.0 kg = 10 kg

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3 years ago

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Katarina [22]

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3 years ago

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const2013 [10]

Explanation:

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$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

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$\epsilon_{o}$ = $8.85 \times 10^{-12}$

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= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

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Leya [2.2K]

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