Answer:
8.1g
0.1g
Explanation:
The reaction expression is given as:
Fe + 2HBr → FeBr₂ + H₂
Mass of pure iron given = 2.8g
A. Mass of HBr needed to dissolve a padlock of the mass;
To solve this problem, we need to use the mole concept.
Convert mass of the known iron to the number of moles.
Number of moles =
Molar mass = 56g/mol
Number of moles of iron =
= 0.05mole
1 mole of Fe will react with 2 mole of HBr
0.05mole of Fe will react with 0.05 x 2 = 0.1mole of HBr
Mass of HBr = number of moles x molar mass
Molar mass of HBr = 1 + 80 = 81g/mol
Mass of HBr = 0.1 x 81 = 8.1g
B. What mass of H2 would be produced by the complete reaction of the iron bar
Since:
1 mole of Fe will produce 2 mole of hydrogen gas
0.05mole of Fe will produce 2 x 0.05mole = 0.1mole of hydrogen gas
Mass of hydrogen gas = number of moles x molar mass
= 0.1 x 1
= 0.1g
Explanation:
it varies due to ph difference
Hcl or hydrochloric acid has a very low ph (about 1) and formic acid has a higher 1
the lower the ph the more acidic and corrosive it making it stronger
hope this helps
The answer for this question would be “but-“
The element that is a nonmetal, a gas, and has an element symbol that starts with the letter a is Ar (Argon).
Element Ar (Argon) is the third member of noble gases, in period 8, and makes up about 1% of the Earth's atmosphere. It has approximately the same solubility as oxygen and it is 2.5 times as soluble in water as nitrogen. It is an inert element that is colorless and odorless in both its liquid and gaseous forms.
<u><em>Answer:</em></u>
Correct option is D.
It accelerates the reaction rates of a mixture.
<u><em>Explanation:</em></u>
It is used to speed up a reaction by lowering the activation energy.Catalysis is the backbone of many industrial processes, which use chemical reactions to turn raw materials into useful products.
<u><em>Types</em></u>
There are two types of catalyst (1) Homogeneous (2) Heterogeneous
In a heterogeneous reaction, the catalyst is in a different phase from the reactants. In a homogeneous reaction, the catalyst is in the same phase as the reactants.