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IgorLugansk [536]
2 years ago
5

How many atoms of chlorine are represented below? 9NaCL

Chemistry
1 answer:
Margaret [11]2 years ago
6 0

Answer:

there are 9 Chlorine atoms

Explanation:

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PLEASE I REALLY NEED ANSWER REAL QUICK
DENIUS [597]

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \frac{5}{100} × 800

                       = 5 × 8

                       = 40 g

The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

                               = 800 - 40

                              = 760 g

Therefore, the mass of water required is 760 g.

5 0
3 years ago
328. mL of 0.00345 M NaI (aq) is combined with 703. mL of 0.00802 M Pb(NO3)2 (aq). Determine if a precipitate will form given th
Vsevolod [243]

Answer:

The solution will not form a precipitate.

Explanation:

The Ksp of PbI₂ is:

PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)

Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>

When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:

[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>

[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>

<em />

Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>

If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.

Replacing:

Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹

As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.

6 0
3 years ago
In calcium fluoride, what is the closets noble gas that each ion becomes?
alekssr [168]
Calcium fluoride: CaF₂
Ca(2+) >>> Ar (argon)
F(-) >>> Ne (neon)
4 0
2 years ago
Approximately, how many national parks are there in the United States? a. 25 b. 50 c. 120 d. 474
Len [333]
B, I would believe. There are 58, but B is the closest we can get.
7 0
2 years ago
Read 2 more answers
Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of
pantera1 [17]

Answer:

W=5743.1077\ J

Explanation:

The expression for the work done is:

W=RT \ln \left( \dfrac{P_1}{P_2} \right)

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)

W=300\times \:8.314\ln \left(10\right)

W=2.30258\times \:2494.2

W=5743.1077\ J

5 0
3 years ago
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