After the water is boiled off, the mass is 9.7 grams, so find the weight of the water.
12.98 - 9.7 = 3.28g H2O
Find how many moles of CuSO4 and H2O you have.
If there are about 18g per mole of H2O
3.28/18 = .1822 moles of H2O
If there are about 160g per mole of CuSO4
9.7/160 = .0606 moles of CuSO4
.1822/.0606 = 3
Ratio of H2O to CuSO4 = 1:3
Formula
<span>CuSO4.3H2O
</span>
Full Name
<span>Copper (II) Sulphate Trihydrate</span>
Antoine Lavoisier was part of a wealthy family in Paris. He pursued to study science upon realizing that chemistry or the study of the elements was not a well-studied field. His discovery of that air was a mixture of nitrogen and oxygen gave rise to the concept of COMBUSTION after repeating the experiments made by Priestly using mercury and other metal oxides.
The event was such a history-making because it disproved that concept that air was a pure substance along with 3 others: earth, fire, and water.
1) Reaction:
Mg(s) + 2HCl (aq) ----> H2(g) + MgCl2(aq)
2) Analysis
An increase in pressure affects directly the rate of reaction involving reactiong gases. Changing the pressure where there are only solids or liquids does not affect the rate of reaction.
This reaction is not an equilibrium, the reaction is only forward. So, the reacting components, Mg(s) and HCl(aq) are a solid and a liquid.
Therefore, the reaction is not affected by the change in pressure.
Answer: the reaction is not affected at all.
Answer:
Explanation:
her is the answer hope this helps
Answer:
kp= 3.1 x 10^(-2)
Explanation:
To solve this problem we have to write down the reaction and use the ICE table for pressures:
2SO2 + O2 ⇄ 2SO3
Initial 3.4 atm 1.3 atm 0 atm
Change -2x - x + 2x
Equilibrium 3.4 - 2x 1.3 -x 0.52 atm
In order to know the x value:
2x = 0.52
x=(0.52)/2= 0.26
2SO2 + O2 ⇄ 2SO3
Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm
Equilibrium 2.88 atm 1.04 atm 0.52 atm
with the partial pressure in the equilibrium, we can obtain Kp.
