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Ierofanga [76]
3 years ago
9

Summarize the characteristics of each type of element below

Chemistry
1 answer:
aniked [119]3 years ago
7 0
What are the elements?
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Mice21 [21]

Answer:

0.675

Explanation:

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To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution
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We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

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The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

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Does a molecule want a geometry that has high energy of low energy
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The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
ziro4ka [17]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

4 0
3 years ago
density of a sample of tin is 8 g/'ll when the actual density was 7.28 g/ml. what was the percentage error
riadik2000 [5.3K]

9.9%

|Approximate Value − Exact Value| divided by

|Exact Value| X 100

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