4 years ago

How much kinetic energy is in a 0.145kg baseball thrown at 35.8 m/s ?

1 answer:

4 0

K= (1/2) m v^2
so 0.5*0.145*<span>1281.64=92.92J of KE</span>

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Basile [38]

Answer:

Explanation:

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AleksAgata [21]

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

$I=F \Delta t=m \Delta v$

where

F is the force exerted by the hammer

$\Delta t=0.08 s$ is the time of contact

$m=2.5 kg$ is the mass

$\Delta v=20 m/s$ is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

$F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N$

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vfiekz [6]

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3 years ago