Answer:


Explanation:
Given:
- flow rate of water,

<em>∵Density of water is 1 kg per liter</em>
∴mass flow rate of water, 
- height of pumping,

- efficiency of motor drive,

- diameter of pipe,

<u>Now the power required for pumping the water at given conditions:</u>



<u>Hence the electric power required:</u>



<u>Flow velocity is given as:</u>

where: a = cross sectional area of flow through the pipe


<span>The value of the constant needed to complete in joules to three significant figures is 2.18 x 10^-18 J.</span>
Answer:
The average forces would be the same
Explanation:
Both have the same velocity on impact as they fell from the same height.
Both have the same velocity after the bounce because they reach the same height.
Both have the same mass
Both will thus experience the same impulse because both have the same change in momentum.
Therefore both experience the same average force.
Answer:
I'm pretty sure the answer is 0 m/s²
Explanation:
The horizontal velocity of the second rock is 5 m/s, so if we pretend air resistance doesn't exist, it will maintain that horizontal velocity, meaning that there is no horizontal acceleration.
Work needed = 23,520 J
<h3>
Further explanation
</h3>
Given
height = 12 m
mass = 200 kg
Required
work needed by the crane
Solution
Work is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = F x d
W = Work, J, Nm
F = Force, N
d = distance, m
F = m x g
Input the value :
W = mgd
W = 200 kg x 9.8 m/s²x12 m
W = 23520 J