Answer:
r = 0.491 m
Explanation:
In this case the System is formed by the teacher with the two masses, so the forces during movement are internal and the angular momentum is conserved
Initial.
L₀ = I₀ w₀
Final
Lf = I w
L₀ = Lf
I₀ w₀ = I w
The moment of inertia is
I₀ = m r₀²
I = m r²
Let's replace
m r₀² w₀ = m r² w
r² = r₀² w₀ / w
Angular velocity
w₀ = 10 rpm (2pi rad / 1 rev) (1 min / 60 s) = 1.047 rad / s
w = 32.5 rpm = 3.403 rad / s
Let's calculate
r = √(0.785 1.047 / 3.403)
r = 0.491 m
Answer:
Acceleration = 2.8 m/s²
Explanation:
Given the following data;
Mass = 1500 kg
Net force = 4200 Newton
To find the truck's acceleration;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
Substituting into the formula, we have;
Acceleration = 2.8 m/s²
The correct answer to the question is C).Dry ice changes to carbon dioxide when kept in an open container.
EXPLANATION:
Before answering this question, first we have to understand sublimation.
Sublimation is a thermal process of state or phase change in which solid substance is directly converted into gas without melting i.e the substance won't undergo liquid state.
In the given question, dry ice is given. Dry ice is the solid state of carbon dioxide. When the dry ice changes to carbon dioxide, directly solid carbon dioxide is converted into gaseous carbon dioxide. No liquid carbon dioxide is formed . So, the phase change is from solid to gas.
Hence, the conversion of dry ice into carbon dioxide is an example of sublimation.
Answer:
the gravitational force between the satellite and the planet is 32.4 * 10³N
Explanation:
It is given that,
Mass of the satellite, m = 6500 kg
Speed of the satellite, v = 6.7 × 10³ m/s
distance to the center of the planet = 9 × 10⁶m
Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :
![F = \frac{mv^2}{R}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bmv%5E2%7D%7BR%7D)
![F = \frac{6500 \times (6.7 * 10^3)}{9 * 10^6}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B6500%20%20%5Ctimes%20%286.7%20%2A%2010%5E3%29%7D%7B9%20%2A%2010%5E6%7D)
= 32.4 * 10³N
the gravitational force between the satellite and the planet is 32.4 * 10³N