Question

the pilot of a new stealth helicopter which has a mass of 15000 kg and was traveling 180 m / s accelerated to 250 m / s in six seconds to make sure he could rescue those in need how much force was used to accelerate the helicopter and what was the helicopters final momentum ​

Answer 1

Answer:

pf = 3750000 kg.m/s

F = 175000 N

Explanation:

Constant Acceleration

An object moves with constant acceleration if its velocity changes uniformly in time.

If we call vo to the initial speed, vf the final speed, and t the time, then the acceleration is calculated as:

$\displaystyle a=\frac{v_f-v_o}{t}$

The new stealth helicopter was traveling at vo=180m/s and changed to vf=250 m/s in t=6 seconds, thus the acceleration was:

$\displaystyle a=\frac{250-180}{6}$

$a=11.67~m/s^2$

Please note this number is shown rounded to the nearest hundredth, but it was stored in the calculator's memory with full precision. This fact affects the next calculation as will be noted below.

The acceleration must be produced for some net force that can be calculated by:

F = m.a

Where m=15000 Kg is the mass of the helicopter. Thus:

F = 15000 * 11.67

F = 175000 N

The above product would lead to the inaccurate result of 175050 if the acceleration would have not used with its full representation in the calculator's memory.

The momentum of an object of mass m and velocity v is:

p = m. v

The final momentum of the helicopter is:

pf = m.vf = 15000*250 m/s

pf = 3750000 kg.m/s

Note: When performing calculations over intermediate results, it's important to keep them as accurate as possible to preserve the accuracy of the final result.