Question

if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring

Answer 1

So what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)
    
here ,
energy required = 10.0°C                Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C    Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= $\frac{10}{3.1*17.9}$
 
                                   = $0.1802126509$
      
                                   = 0.1802 cal./g°C            i rounded the answer to the                                                                                      fourth decimal point