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ladessa [460]
3 years ago
5

Please help me

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

The lines are perpendicular, meaning if they were to intersect, they would form four right angles.

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What is the value of this expression?<br><br> 6⋅[(32−8)÷4+2]
4vir4ik [10]
Answer: 24

Step by step explanation:
6 0
4 years ago
Factor 7w2−175.(1 point)<br><br> −7(w−25)<br><br> 7(w−25)<br><br> 7(w−5)(w+5)<br><br> 7(w−5)(w−5)
Nutka1998 [239]

Answer:

7(w + 5)(w -5)

Step-by-step explanation:

a² - b² = (a + b)(a - b)

7w² - 175 = 7w² - 7*25

              = 7(w² - 25)

              = 7(w² - 5²)

              = 7(w + 5)(w -5)

6 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
For f(X)=2x+1 and g(X)=x^2,find (f-g)(X)
Bezzdna [24]

The answer for f(x)-g(x) is -x^2+2x+1.The solution can be obtained by use of concept of functions.

<h3>What is a function?</h3>

A function, in mathematics, can be defined as an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).It useful in mathematical representation of scientific quantities.

We can perform addition and subtraction operations on functions.

The given function f(x) and g(x) are

f(x)=2x+1\\g(x)=x^2\\f(x)-g(x)=2x+1-x^2\\f(x)-g(x)=-x^2+2x+1

The solution for f(x)-g(x) is -x^2+2x+1.

To know more about functions visit:

brainly.com/question/12431044

#SPJ9

3 0
1 year ago
In a mathematics class, half of the students scored 79 on an achievement test. With the exception of a few students
Yakvenalex [24]
In this situation, you have:
The mode is 79 (that’s the most common number).
The median is 78.5 (the middle value or the average of the two middle values, since there is an even number of test scores).
The mean is less than both of those, as it was brought down by the few scores of 49.

The means the mean will be less than median.

Answer: C
3 0
3 years ago
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