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lesantik [10]
3 years ago
12

HELP DUE IN 15 MINS! ΔLMN ~ ΔPQR. Which of the following sets of side lengths could be those of ΔLMN?

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0

Answer:

  • D. 9 cm, 12 cm, 15 cm

Step-by-step explanation:

<u>Given</u>

  • ΔLMN ~ ΔPQR

ΔPQR has sides ratio 3 : 4 : 5

ΔLMN should also have same ratio and the ratio of corresponding sides should be same.

<u>Let's verify the options:</u>

<u>A. 2 : 3: 4</u>

  • 2/3 = 3/4 = 4/5 - this is incorrect

<u>B. 6 : 7 : 8</u>

  • 6/3 = 7/4 = 8/5  - this is incorrect

<u>C. 8 : 15 : 17</u>

  • 8/3 = 15/4 = 17/5  - this is incorrect

<u>D. 9 : 12 : 15</u>

  • 9/3 = 12/4 = 15/5 = 3  - this is correct
yulyashka [42]3 years ago
3 0

Answer: D.

Step-by-step explanation:

If the triangle PQR has sides from biggest to smallest 3,4,5 we need another triangle with a similar ratio to compare it to.

9/3= 3  12/3=4   15/3=5

So the answer is D because I can divide all the sides of the new triangle by the same number to get the sides of triangle PQR

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lisov135 [29]
Three times = 3 × 

<span>The difference of 65 and 48 = 65 - 48 = 17
(Difference = subtract)

That equals 3 </span>× 17 
<span>
Answer = 3 </span>× 17 
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Hope this helped☺☺

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3 years ago
What is the exponent for 50,000,000
Tom [10]
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Help me ASAP PLEASE lateral surface area of the triangular prism :)
Lerok [7]

Answer:

15+15+40+40+40= 150

Step-by-step explanation:

Triangle x2]

(5 x 6) / 2

15

Rectangle x3]

(8 x 5)

40

only for a triangle, we divide by 2

Your answer is <u>150cm square.</u>

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3 years ago
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
lesya692 [45]

Answer:

The probability that a call last between 4.2 and 4.9 minutes is 0.4599

Step-by-step explanation:

Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

W = \frac{X-\mu}{\sigma} = \frac{X-4.2}{0.4}

We will use \phi , the cummulative distribution function of W. The values of \phi are well known and the can be found in the attached file

P(4.2 < X < 4.9) = P(\frac{4.2-4.2}{0.4} < \frac{X-4.2}{0.4} < \frac{4.9-4.2}{0.4}) = P(0 < W < 1.75) = \\ \phi(1.75) - \phi(0) = 0.9599-0.5 = 0.4599

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599

Download pdf
7 0
3 years ago
Can you answer this one for my plz I need before Monday ty
ira [324]
Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5

The vertex is (-2, 5).
The axis of symmetry is x = -2.

7 0
3 years ago
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