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2 years ago

The equation y-4=-3(x+4) is written in point-slope form. What is the y-intercept of the line

Mathematics

2 answers:

cricket20 [7]2 years ago

8 0

Answer:

-8

Step-by-step explanation:

you need to rewrite it in y=mx+b form where b-is the y-intercept

y-4= -3(x+4)

distribute

y-4 = -3x-12

isolate y

y= -3x-8

compare this with the y=mx+b so y-intercept is -8

Anit [1.1K]2 years ago

8 0

Answer:

(0,-8)

Step-by-step explanation:

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Y = 6x − 11 −2x − 3y = −7 *

Deffense [45]

6x - 11 - 2x = -7
4x - 11 - = -7
4x = 11
X= 2
12- 11 -4 -3y = -7
-3 -3y = -7
-3y = -4
Y = -1

It should be 2,-1

5 0

3 years ago

What is the solution set of the equation using the quadratic formula?

oee [108]

(1)

we are given

$x^2+6x+10=0$

we can use quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a , b and c

we get

$a=1,b=6,c=10$

now, we can plug these values into quadratic formula

$x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}$

$x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

we can simplify it

$x=-3+i$

$x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

$x=-3-i$

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

$x^2-8x+14=0$

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so, subtract both sides by 14

$x^2-8x+14-14=0-14$

$x^2-8x=-14$

we can write

$-8x=-2\times 4\times x$

so, we will add both sides by 4^2

$x^2-8x+4^2=-14+4^2$

we get

$x^2-8x+16=-14+16$ ..............Answer

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2 years ago

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2 years ago

Find the value of x please help

Nezavi [6.7K]

9514 1404 393

Answer:

x = 12

Step-by-step explanation:

The right triangles are all similar, so the ratios of long to short ides are the same:

x/6 = 6/3

x = 6(6/3) . . . multiply by 6

x = 12

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3 years ago

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