Write down 3 integers, all less than 25 whose range is 8 and mean is 13

Mathematics

1 answer:

EleoNora [17]3 years ago

6 0

Answer:

9, 13, 17

Step-by-step explanation:

The difference between the greatest value and the least is 8, the range.

Add the three numbers to total 39, then divide by 3 to get the mean, 13.

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Select Exponential growth or Exponential decay for each function.

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Answer:

f(x)=(1.023) ⋅ 3^x Growth

f(x)=3 ⋅ (0.072)^x Decay

f(x)=4 ⋅ (0.035)^x Decay

f(x)=2 ⋅ (1.34)^x Growth

Step-by-step explanation:

An exponential function at its heart has a base number of rate. If the rate is less than 1, then the function decays. If the base number or rate is greater than 1, then the function grows and increase.

f(x)=(1.023) ⋅ 3^x Rate 3 - Growth

f(x)=3 ⋅ (0.072)^x Rate 0.072 - Decay

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3 years ago

If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the

Aleks [24]

OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13

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To graph a rate or ratio from a table, how do you determine the scales to use on each axis?

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The acceleration in centimeters per second of a projectile is modeled by

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Answer:

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2 years ago

Instructions

PilotLPTM [1.2K]

I chose a box of cereal-------> rectangular prism
see the attached figure

Part 1)List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.).
Length: 20 cm
Width: 8 cm
Height: 32 cm

Part 2).
Describe the shape of the cross-section when the box is cut parallel to the base

the shape of the cross-section would be a rectangle of dimensions
20 cm x 8 cm

Part 3)
What is the surface area of the box?

surface area=2*area of the base+perimeter of the base*height

area of the base=20*8=160 cm²

perimeter of the base=2*[20+8]-----> 56 cm
height=32 cm

surface area=2*160+56*32------> 2,112 cm²

the answer part 3) is
2,112 cm²

Part 4)
What is the surface area of the box if it is scaled up by a factor of 10?

we know that
surface area of the larger box=[scale factor]²*surface area original box

scale factor=10
surface area original box=2,112 cm²
so
surface area of the larger box=10²*2,112-----> 211,200 cm²

the answer part 4) is
211,200 cm²

Part 5)
What is the volume of the box?

volume of the box=L*W*H-----> 20*8*32------> 5,120 cm³

the answer Part 5) is
5,120 cm³

Part 6)
What is the volume of the box if it is scaled down by a factor of 1/10

we know that
volume of the smaller box=[scale factor]³*volume original box
scale factor=1/10
volume original box=5,120 cm³
so
volume of the smaller box=[1/10]³*5,120-----> 5.12 cm³

the answer part 6) is
5.12 cm³

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3 years ago