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Helga [31]
3 years ago
7

Simultaneous equations x^2+3xy=10 x=2y

Mathematics
1 answer:
satela [25.4K]3 years ago
8 0

9514 1404 393

Answer:

  (x, y) = (-2, -1) or (2, 1)

Step-by-step explanation:

Substitute for x in the first equation:

  (2y)^2 +3(2y)y = 10

  10y^2 = 10

  y^2 = 1

  y = ±1

  x = 2y = ±2

Solutions are (x, y) = (-2, -1) or (2, 1).

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If the pictured triangles are congruent what reason can be given
igor_vitrenko [27]

Answer:

SAS Postulate.

Step-by-step explanation:

Two triangles are congruent if anyone of the following postulates is true:

SAS - Two corresponding sides and the included angles are congruent to each other.

SSS - All the three corresponding sides are congruent.

ASA - Two corresponding angles and the included sides are congruent to each other.

AAS - Two corresponding consecutive angles and sides adjacent to either of the angles are congruent.

HL - If the corresponding hypotenuses and one corresponding legs are congruent to each other.

Here, in the figure, two corresponding sides and the included angle between them are congruent to each other.

So, the two triangles are congruent by SAS postulate.

8 0
3 years ago
Complete the solution of the equation. Find the
kykrilka [37]

Answer:

1/80

Step-by-step explanation:

-8*5*xy= -1

Sub 2 for x

-8*5*2*y= -1

-80y=-1

y=1/80

(i was kinda confused because i wasn't sure if the x was a variable or a multiplication symbol but i made it a variable) yea

5 0
2 years ago
A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c
mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

So

P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

P(A \cap B) = 0.6*\frac{1}{6} = 0.1

Find the probability that bridge B was used.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333

0.1333 = 13.33% probability that bridge B was used.

8 0
3 years ago
What is the greatest common factor of 12x 16x 8x
slega [8]

Answer:

4x

Step-by-step explanation:

The Factors of 12

1,12, 2,6 3,4

16

1,16 2,8 4,4

8

1,8 ,2,4

The highest factor they share is 4 so it would be the GCF. Then you would have to add the x back into the GCF

Hope It helped

8 0
3 years ago
The area of a rectangular piece of plastic is 10 square millimeters. The perimeter is 22 millimeters. What are the dimensions of
Serhud [2]
2789 dimensions because it’s simple u multiple them
4 0
3 years ago
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