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3 years ago

How do i explain this

Physics

1 answer:

Roman55 [17]3 years ago

6 0

Answer:

well I don't think there is anything to say about it or the question is not complete

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Whích phase change is the result of particles moving more quickly? (2 points)

sdas [7]

Answer:

liquid to gas

Explanation:

let me know if this helps

8 0

3 years ago

A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x

DedPeter [7]

Answer:

The electric field at x = 3L is 166.67 N/C

Solution:

As per the question:

The uniform line charge density on the x-axis for x, 0< x< L is $\lambda$

Total charge, Q = 7 nC = $7\times 10^{- 9} C$

At x = 2L,

Electric field, $\vec{E_{2L}} = 500N/C$

Coulomb constant, K = $8.99\times 10^{9} N.m^{2}/C^{2}$

Now, we know that:

$\vec{E} = K\frac{Q}{x^{2}}$

Also the line charge density:

$\lambda = \frac{Q}{L}$

Thus

Q = $\lambda L$

Now, for small element:

$d\vec{E} = K\frac{dq}{x^{2}}$

$d\vec{E} = K\frac{\lambda }{x^{2}}dx$

Integrating both the sides from x = L to x = 2L

$\int_{0}^{E}d\vec{E_{2L}} = K\lambda \int_{L}^{2L}\frac{1}{x^{2}}dx$

$\vec{E_{2L}} = K\lambda[\frac{- 1}{x}]_{L}^{2L}] = K\frac{Q}{L}[frac{1}{2L}]$

$\vec{E_{2L}} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{2L}] = \frac{63}{L^{2}}$

Similarly,

For the field in between the range 2L< x < 3L:

$\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx$

$\vec{E} = K\lambda[\frac{- 1}{x}]_{2L}^{3L}] = K\frac{Q}{L}[frac{1}{6L}]$

$\vec{E} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{6L}] = \frac{63}{6L^{2}}$

Now,

If at x = 2L,

$\vec{E_{2L}} = 500 N/C$

Then at x = 3L:

$\frac{\vec{E_{2L}}}{3} = \frac{500}{3} = 166.67 N/C$

4 0

4 years ago

Why doesn't the principle of mechanical energy conservation hold in situations when frictional forces are present?

vodomira [7]

When you are talking about the Principle of mechanical Energy Conservation, it is really only including the kinetic and potential energy in a total system. When frictional forces are present, although the conservation of energy law is still present, it does not work when it comes to the conservation of mechanical energy as there is another type of energy that is factored in. As friction acts on the object, that transition from potential to kinetic as it slide/falls will be completely different as some of that energy is being transformed into thermal energy. Which breaks the conservation of mechanical energy.

7 0

3 years ago

The atomic number of Krypton si 36. if the mass number of a Krypton atom si 84, which table shows the number of subatómico insid

Elan Coil [88]

Answer:

Explanation:

You did not list the options. However, knowing the possible options from having seen the material myself - I can infer that the answer option is A. I apologize sincerely if this is wrong.

3 0

3 years ago

Consider the power dissipated by the two circuits in the video. The ratio of power dissipation in the parallel circuit to that i

rjkz [21]

Answer:

D. 1/9

Explanation:

Firstly, draw the circuits, then you solve for resistance in series with the formula- R1 + R2... And in parallel- 1/R1 + 1/R2...

Then after getting your resistance, use the formula for power that relates with resistance and voltage.

This the ratio will be 1/9. The parallel circuit has 1/9 the resistance of the series circuit. Since the potential difference across the two circuits is the same, this implies that the parallel circuit will give out 9 times more power than the series circuit.

3 0

3 years ago

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How do i explain this​

How do i explain this