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N76 [4]
3 years ago
6

Consider the power dissipated by the two circuits in the video. The ratio of power dissipation in the parallel circuit to that i

n the series circuit is_______________.
A) 9
B) 3
C) 1
D) 1/9
E) 1/3
Physics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

A) 9

Explanation:

The power dissipation in a circuit can be estimated using any of the equations below:

P = V*I

P = V^2/R

P = I^2 * R

Where:

P is the power dissipated, I is the current that flows through the circuit, V is the potential difference, and R is the equivalent resistant. Therefore, using the parameters provided and one of the formulas above:

Power dissipated (parallel circuit) : Power dissipated (Series circuit) = 9:1 = 9

rjkz [21]3 years ago
3 0

Answer:

D. 1/9

Explanation:

Firstly, draw the circuits, then you solve for resistance in series with the formula- R1 + R2... And in parallel- 1/R1 + 1/R2...

Then after getting your resistance, use the formula for power that relates with resistance and voltage.

This the ratio will be 1/9. The parallel circuit has 1/9 the resistance of the series circuit. Since the potential difference across the two circuits is the same, this implies that the parallel circuit will give out 9 times more power than the series circuit.

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3 years ago
Oil having a specific gravity of 0.9 is pumped as illustrated with a water jet pump. The water volume flowrate is 1 m3 /s. The w
love history [14]

Answer:

The rate at which the pump moves oil is 1 m³/s

Explanation:

Assumptions:

  • there is steady-state flow
  • oil and water are incompressible
  • first fluid is water, second fluid is oil and third fluid is the mixture of oil and water.

\rho_1Q_1 + \rho_2Q_2 = \rho_3Q_3 -------equation (i)

where;

ρ is the fluid density

Q is the volumetric flow rate

Q_1 + Q_2 = Q_3--------equation (ii)

Substitute in Q₃ in equation i

\rho_1Q_1 + \rho_2Q_2 = \rho_3(Q_1 +Q_2)

divide through by ρ₁

\frac{\rho_1Q_1}{\rho_1}+ \frac{\rho_2Q_2}{\rho_1} =\frac{ \rho_3(Q_1 +Q_2)}{\rho_1}\\\\Note; \frac{\rho_2}{\rho_1} = \gamma_2 \ and \ \frac{\rho_3}{\rho_1} = \gamma_3\\\\Q_1 + \gamma_2Q_2 = \gamma_3(Q_1+Q_2)

Make Q₂ the subject of the formula

Q_2 = \frac{Q_1(1- \gamma_3)}{\gamma_3-\gamma_2} = \frac{1 (\frac{m^3}{s}) (1-0.95)}{0.95-0.9} = 1 \ \frac{m^3}{s}

Therefore, the rate at which the pump moves oil is 1 m³/s

6 0
3 years ago
Horizontal angulation is: Select one: a. the side-to-side angulation. b. different when using the paralleling and bisecting tech
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Horizontal angulation is Select one: a. the side-to-side angulation. b. different when using the paralleling and bisecting techniques.

Angles that are horizontal. relates to the central ray's placement in a horizontal, or side-to-side, plane.

A picture with an overlap of nearby structures in the horizontal plane is produced by situating the central ray such that the horizontal angulation is not directed through the interproximal contacts of the adjacent teeth (the contact areas of the teeth are superimposed over each other).

Fracture angulation refers to a particular kind of fracture displacement in which the bone's natural axis has been changed so that the distal end now points off in a different direction. When using a bite-wing tab, the x-ray beam's center ray must be pointed at the contact points between teeth. The x-ray beam must be centered on the receptor to guarantee that the receptor is exposed.

Learn more about horizontal angulation  here brainly.com/question/28043105

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8 0
2 years ago
Air is being pumped into a spherical balloon so that its volume increases at a rate of 150 cm3/s. How fast is the radius of the
Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

dv/dt = 150cm³/s

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dv/dt =  4/3π(3r²)dr/dt = 4πr²dr/dt

Hence,

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dr/dt = 1/4π×(10)²×150

dr/dt = 1/4π×100×150

dr/dt = 0.119cm/s.

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What part of an electric circuit are the wires that carry the electric current
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Answer:

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